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4 years ago

Solve the equation. Use a calculator. d^3 =3

Mathematics

1 answer:

barxatty [35]4 years ago

7 0

Answer:

d ≈ 1.4

Step-by-step explanation:

Step 1: Write equation

d³ = 3

Step 2: Take cube root of both sides

d = ∛3

Step 3: Evaluate

d = 1.44225

Step 4: Round

d ≈ 1.4

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X2 - 8x + 15 = 0<br> quadratic formula

ivanzaharov [21]

The quadratic formula is x=(-b+-sqrt(b^2-4(a)(c)))/2a

Using the quadratic formula, we get:

x=(-(-8)+-sqrt((-8)^2-4(15)(1)))/2(1)

x=(8+-sqrt(64-60))/2

x=(8+-sqrt(4))/2

x=(8+-2)/2

x=10/2 and x=6/2

x=5 and x=3

We could do it way faster by completing the square:

x^2-8x+15=0

(x-5)(x-3)=0

x=5 and x=3

Hope both methods make sense! BTW, the +- thing means add or subtract

6 0

4 years ago

What is the point called where 2 lines intersect or cross? It is the ___________ to the system of equations

Oxana [17]

Answer:

Step-by-step explanation:

The point where the lines intersect is called the point of intersection.These form opposite angles.

7 0

3 years ago

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Find the length of the side of a square with an area of 25

Alexxx [7]

Area squares is the side*side, or
$x^{2} =25$
$\sqrt{ x^{2} } = \sqrt{25}$
$x=5$

So, each side equals 5.

4 0

3 years ago

A piece of cardboard is 1 meter by 1/21/2 meter. A square is to be cut from each corner and the sides folded up to make an open-

12345 [234]

Answer:

The maximum dimensions of the box:

Length of the box = 0.788676 m

Breadth of the box = 0.288676 m

Step-by-step explanation:

Original piece of cardboard is a square with sides of length s.

Length of the card board = l = 1 m

Breadth of cardboard = b = 1/2 m = 0.5 m

Squares with sides of length x are cut out of each corner of a rectangular cardboard to form a box.

Now, length of the box = L = 1 - 2x

And breadth of the box = B = 0.5 - 2x

Height of the box ,H = x

Volume of the box ,V= L × B × H

$\frac{dV}{dx}=\frac{(1 -2x)(0.5-2x)x}{dx}$

$\frac{dV}{dx}=\frac{d(0.5x-3x^2+4x^3)}{dx}$

$\frac{dV}{dx}=0.5-6x+12x^2$

$\frac{dV}{dx}=O$

x = 0.394338 , 0.105662

$\frac{d^2V}{(dx)^2}=-6+24x$

When , $x=0.105662$ , $\frac{d^2V}{(dx)^2}$ (maxima)

The maximum dimensions of the box:

Length of the box = L = 1 - 2x = 1 - 2(0.105662) m = 0.788676 m

Breadth of the box = B = 0.5 - 2x = 0.5 - 2(0.105662) m = 0.288676 m

6 0

3 years ago

Plz help me like now

djyliett [7]

Answer:

im gonna guess d?

Step-by-step explanation:

cuz it goes up

7 0

3 years ago

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