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3 years ago

Plz help me like now

Mathematics

2 answers:

djyliett [7]3 years ago

7 0

Answer:

im gonna guess d?

Step-by-step explanation:

cuz it goes up

Anni [7]3 years ago

7 0

Answer:

Its B !! i promise

Step-by-step explanation:

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2) Which expression is equivalent to:<br> y•y3•y2

Nastasia [14]

Answer:

y^6

Step-by-step explanation:

When multiplying terms with exponents that have the same base, the rule is to add the exponents. y * y^3 * y^2 = y^(1 + 3 + 2). (remember that y has a hidden exponent of 1, we just don't write that because it is redundant and unnecessary). y^(1 + 3 + 2) = y^6

hope this helps! <3

3 0

2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

3 years ago

-3 = b/6 - 10<br> * B/6 IS DIVISION NOT A FRACTION*<br> Thank you

vodka [1.7K]

Answer:

bro division and fraction are technically same

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A school has 18 classes with 35 students in each class. In order to reduce class size to 30,how many new classes have to be form

Mekhanik [1.2K]

1 class with 5 student

5 0

3 years ago

Read 2 more answers

What is the area of this parallelogram?<br><br> 44 cm²<br><br> 55 cm²<br><br> 99 cm²<br><br> 220 cm²

Art [367]

Here, we can split this parallelogram into two triangles and one rectangle. The triangles are equal to each other so we can just find the area of the rectangle and the are of <span>one triangle.

</span>Triangle area formula: $a= \frac{1}{2} bh$ , where a = area, b=base, and h=height.

Plug in 5 for b and 11 for h:

$\frac{1}{2}*11*5 = \frac{55}{2}$
<span>Multiply by 2!
</span> $\frac{55}{2} *2=55$

Rectangle area formula: a=bh, where a = area, b = base, and h = height.

Plug in 4 for b and 11 for h.

a = 4 x 11
a = 44

44+55 = 99

Area is 99 cm<span>².</span>

7 0

3 years ago

Read 2 more answers