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Ksenya-84 [330]
3 years ago
13

Find the vector and parametric equations for the line through the point p=(−2,0,−3)p=(−2,0,−3) and parallel to the vector ⟨−4,3,

2⟩⟨−4,3,2⟩.
Mathematics
1 answer:
Simora [160]3 years ago
4 0

x =  - 4t - 2
y = 3t
z = 2t - 3
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Alenkasestr [34]

Answer:

I think that the answer is

-g + 12

I used a math check calculator and it said that the above is the answer

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3 years ago
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How do you isolate the variable in 1/2p+75=100
hram777 [196]

Answer:p=50

Step-by-step explanation:

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Someone pls help, its on trig ratios.
Mars2501 [29]

Answer:

BC=12.8,\\AC=15.1

Step-by-step explanation:

In right triangles only, the tangent of an angle is equal to its opposite side divided by its adjacent side.

Therefore, we have the following equation:

\tan 58^{\circ}=\frac{BC}{8}

Solving, we get:

BC=8\tan 58^{\circ}\approx \boxed{12.8}

Also in right triangles only, the cosine of an angle is equal to its adjacent side divided by the hypotenuse of the triangle.

\cos 58^{\circ}=\frac{8}{AC},\\AC=\frac{8}{\cos 58^{\circ}},\\AC\approx \boxed{15.1}

We can also use the Pythagorean theorem now that we've found BC. However, if you choose to do so, make sure you don't use a rounded value for BC, as that could cause a notable deviation in your final answer.

Using the Pythagorean theorem to verify our answers:

8^2+(8\tan 58^{\circ})^2=\left(\frac{8}{\cos 58^{\circ}}\right)^2\:\checkmark

6 0
3 years ago
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 80 mi/h faster than the other. If
Vesna [10]

Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

<h3>How to get the rate of each jet?</h3>

Let's say that the rate (or speed) of the slower jet is R, then the rate of the faster jet is:

R + 80mi/h

Now, if we step on any of the two jets (such that we view it as if it doesn't move) the other jet will move with a speed equal to:

S = R + R + 80mi/h

We know that after 8 hours, the to jets are 11,392 mi apart, then we know that:

(R + R + 80mi/h)*8h = 11,392 mi

Now we can solve that for R:

2*R + 80mi/h = 11,392 mi/8h = 1,424 mi/h

R = 1,424 mi/h - 80mi/h)/2 = 672 mi/h

So Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

If you want to learn more about speed:

brainly.com/question/4931057

#SPJ1

8 0
2 years ago
Pls help will give barainliest
BARSIC [14]

Answer:

i dont know

Step-by-step explanation:

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