Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Width: x
Length: 2x
Perimeter=2x+2x+x+x=6x
32 cm more than width means x+32
6x=x+32
5x=32
x=6.4
Dimension is 6.4×12.8 (width×length)
Answer:
D. (17,-1)
Step-by-step explanation:
We'll start by canceling out x. To do so, multiple the first equation by -1
-1( x - 2y)=( 19 )(-1)
This gives us:
-x +2y = -19
x + 3y = 14
Add the equations together:
→ 5y = -15
→ y = -1
Plug in y = -1 into an equation:
→ x + 3(-1) = 14
→ x - 3 = 14
→ x = 17
(17,-1)
Hope this helps!
Answer:
Option C.
Step-by-step explanation:
We need to translate each phrase and find the different expression.
"+" sign is used for sum, more and total.
Twice means two times of a number.
Let n be the unknown number.
Two more than a number = n+2
The total of n and 2 = n+2
Twice the number n = 2n
Sum of n and 2 = n+2
From the above expressions it is clear that only 2n is different from other.
Therefore, the correct option is C.
Answer:
B
Step-by-step explanation:
I just put in in the desmos graphing calculator