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trasher [3.6K]
3 years ago
12

How many faces does the following shape have?​

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

6 faces. pls mark brainliest

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Using the quadratic formula to solve 5x = 6x²-3, what are the values of x?
Salsk061 [2.6K]

Answer:

\boxed{\sf{x =  \frac{5 \pm \sqrt{97} }{12} }}

Step-by-step explanation:

\sf{5x = 6 {x}^{2} - 3 }

\sf{0 = 6 {x}^{2} - 3 - 5x }

\sf{0 = 6 {x}^{2} - 5x - 3 }

  • a = 6
  • b = - 5
  • c = - 3

\sf{x =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a} }

\sf{x =  \frac{ - ( - 5) \pm \sqrt{ { - 5}^{2}  - 4(6)( - 3)} }{2(6)} }

\sf{x =  \frac{5 \pm \sqrt{ 25   + 72} }{12} }

\sf{x =  \frac{5 \pm \sqrt{97} }{12} }

8 0
2 years ago
HI 3548 + 124689652 - (3553x4636) x 74683 -385 = ??? -654 x45 ???
Luden [163]

Answer:

54686183891711636176871    Dout this is right.........Lol

Step-by-step explanation:

Pls mark brainleist

8 0
3 years ago
I need help plz, i dont understand :(
dedylja [7]

Answer:

Step-by-step explanation:

follow a few exponent rules and you can figure this out

when expoenents are to the power of something you can mutilply the expoents.. and when there is a minus sign in the exponent.. it's like the reciprocal   x^{-2}  is  1/x^{2}    soooo...

mutilply the  -2/3 by each of the exponents in the question the 8 is tricky b/c it has an invisible 1 on it :o

= 8^{-2/3}w^{-14/3}x^{10/3}y^{-6/3}z^{18/3}

= 1/\sqrt[3]{8*8} * 1/w^{14/3} * x^{10/3} * 1/y^{2} * z^{6}

= 1/\sqrt[3]{64}* 1/w^{14/3} *x^{10/3} * 1/y^{2} * z^{6}

= 1/4* 1/w^{14/3} *x^{10/3} * 1/y^{2} * z^{6}

=answer A

5 0
3 years ago
Amie published her first book. She was given $20,000 and an additional $0.15 for each copy that sold. Her earnings,d, in dollars
Harrizon [31]
<span>d=20,009 + 0.15n
</span>$22,100 = 20,009 + 0.15n
$2091 = 0.15n
n = 2091/.15 = 13940
3 0
3 years ago
Read 2 more answers
What is the solution of the following trig equation: tan(theta)(csc(theta)+2)=0
gtnhenbr [62]
D:\theta\neq\frac{k\pi}{2};\ k\in\mathbb{Z}\\\\tan\theta(csc\theta+2)=0\iff tan\theta=0\ \vee\ csc\theta+2=0\\\\\\tan\theta=0\iff\theta=k\pi\notin D\\\\csc\theta+2=0\\\\csc\theta=-2\\\\\frac{1}{sin\theta}=-2\\\\-2sin\theta=1\ /:(-2)\\\\sin\theta=-\frac{1}{2}

(\theta=-\frac{\pi}{6}+2k\pi\ \vee\ \theta=\frac{7\pi}{6}+2k\pi)-answer
7 0
4 years ago
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