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3 years ago

Explain why ethics and skepticism are integral to science.

1 answer:

8 0

Ethics and Skepticism are integral to science because they are the basis for the need to lay explanations on various fields of science through experiment. This will enable science bring the right data and arguments through scientific methods in an accurate and a straight forward manner.

Hope this helped have an awesome day :)

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Which consequence of new fishing methods had the most immediate impact on the environment?

maxonik [38]

I believe the answer is D

4 0

3 years ago

Read 2 more answers

Under which conditions would the solubility of a gas be greatest? A. high pressure and high temperature B. high pressure and low

LiRa [457]

Answer:

High pressure and low temperature.

Explanation:

8 0

3 years ago

A sample of gas is held at 1000C at a volume of 20 L. If the volume is increased to 40 L, what is the new temperature of the gas

kaheart [24]

Answer:

The new temperature will be 2546 K or 2273 °C

Explanation:

Step 1: Data given

The initial temperature = 1000 °C =1273 K

The volume = 20L

The volume increases to 40 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 20L

⇒with T1 = the initial temperature = 1273 K

⇒with V2 = the increased volume = 40L

⇒with T2 = the new temperature = TO BE DETERMINED

20L/ 1273 K = 40L / T2

T2 = 40L / (20L/1273K)

T2 = 2546 K

The new temperature will be 2546 K

This is 2546-273 = 2273 °C

Since the volume is doubled, the temperature is doubled as well

8 0

3 years ago

How to balance the equation HNO3 + Ca(OH)2 --> Ca(NO3)2 + H20

Colt1911 [192]

2HNO3 + Ca(OH)2 —> Ca(NO3)2 + 2H2O

3 0

3 years ago

Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha

fenix001 [56]

Answer:

$\boxed{\text{2.274 mol/L}}$

Explanation:

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}$

Assume 1 kg water.

1. Moles of P.HCl

Then we have 4.666 mol of P.HCl

2. Mass of P.HCl

n = 4.666 mol × 272.77 g/mol = 1271.1 g

3. Total mass of solution

m = 1000 g + 1271.1 g = 2271.1 g solution

4. Volume of solution

$V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}$

5. Molar concentration

$\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\$

$\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}$

5 0

4 years ago