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3 years ago

13

HELP PLEASE WITH 1 QUESTION.

1 answer:

Nata [24]3 years ago

8 0

The activity series goes top to bottom, most active to least active elements, going: Li, K, Ba, Sr, Ca, Na, Mg, Mn, Zn, Fe, Cd, Co, Ni, Sn, Pb, H, Cu, Ag, Hg, Au.

Thus, your list of metals would go from most reactive to least reactive: Li, K, Mg, Zn, Fe, Cu, Au

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A student performing this experiment weights out 0.6680 grams of an antacid tablet. It is was determined that this tablet contai

Rufina [12.5K]

Answer:

63 wt%

Explanation:

0.4210/0.6680

3 0

3 years ago

Formaldehyde organic or inorganic

scZoUnD [109]

Formaldehyde is an organic compound.

8 0

4 years ago

Atoms of which two elements have a combined total of 23 protons?

Alik [6]

Answer:

Sodium, Na, and magnesium, Mg

6 0

4 years ago

The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P

expeople1 [14]

Answer : The ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

Solution : Given,

$K_p=1.5\times 10^6$

$p_{O_2}$ = 0.21 atm

The given equilibrium reaction is,

$NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}$

Now put all the given values in this expression, we get:

$1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}$

$\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}$

$\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5$

Therefore, the ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

5 0

3 years ago

Please help , science tho. by the way i have to do 5

kap26 [50]

Answer:

850

Explanation:

It's between 840 and 860

8 0

2 years ago