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oksian1 [2.3K]
3 years ago
13

HELP PLEASE WITH 1 QUESTION.

Chemistry
1 answer:
Nata [24]3 years ago
8 0
The activity series goes top to bottom, most active to least active elements, going: Li, K, Ba, Sr, Ca, Na, Mg, Mn, Zn, Fe, Cd, Co, Ni, Sn, Pb, H, Cu, Ag, Hg, Au. 

Thus, your list of metals would go from most reactive to least reactive: Li, K, Mg, Zn, Fe, Cu, Au
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ANSWER FAST PLZZZ!!!!!!!!!!!!!
goldfiish [28.3K]

Answer:

1 and 2

Explanation:

1 is negative

2 is negative

3 is positive

5 0
3 years ago
Find the number of Grams
zaharov [31]

Answer: 462 g

Explanation:molar mass is M= 63.55 +2·(12.01+14.01)= 115.59 g/mol.

Mass m= n·M = 4.0 mol·115.59 g/mol= 462.36 g

8 0
2 years ago
Explain the units and how to solve the following metric conversion then solve the metric conversion by filling in the blank 12KM
LiRa [457]

Answer:- 12 km = 12000 m

Solution:- It's a metric unit conversion where we are asked to convert 12 km to m where km stands for kilometer and m stands for meter.

In metric conversions, kilo means 1000.

So, 1 km = 1000 m

It means,  we multiply the given km by 1000 to get the answer in m as:

12km(\frac{1000m}{1km})

= 12000 m

Hence, 12 km = 12000 m.

5 0
3 years ago
24-Complete the following sentence:
docker41 [41]

Answer:

B. Solvent

Explanation:

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8 0
2 years ago
If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did
user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

Q=m\times c \times \Delta T

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

Plugging in the values  

\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$

So,

Volume of water = mass/density

\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$

=4.5 L (Answer)

6 0
3 years ago
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