Since the number of black cards are 26 (spades and clubs) (13 for each kind). And there are 4 pieces of number 3 on the deck. That gives us 30. So the answer is 30/52.
Answer:
Option (c)
Step-by-step explanation:
Slope of a line that passing through two points M(-1, 4) and N(2, -5),
= 
= 
= -(
)
= -
To find the line perpendicular line to MN we will use the property,

Where
and
are the slopes of two perpendicular lines.
Slope of line perpendicular to MN
will be,


Slope of line joining two points J(-3, -4) and K(3, -2),
Slope = 
Slope of line joining two points A(-3, 2) and B(3, 0)
Slope = 
Slope of the line joining points E(0, -3) and F(2, 3),
Slope =
= 3
Therefore, line EF is perpendicular to the line MN.
Option (c) is the answer.
Answer:
- vertical scaling by a factor of 1/3 (compression)
- reflection over the y-axis
- horizontal scaling by a factor of 3 (expansion)
- translation left 1 unit
- translation up 3 units
Step-by-step explanation:
These are the transformations of interest:
g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k
g(x) = f(x) +k . . . . vertical translation by k units (upward)
g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis
g(x) = f(x-k) . . . . . horizontal translation to the right by k units
__
Here, we have ...
g(x) = 1/3f(-1/3(x+1)) +3
The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:
- vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
- reflection over the y-axis . . . 1/3f(-x)
- horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
- translation left 1 unit . . . 1/3f(-1/3(x+1))
- translation up 3 units . . . 1/3f(-1/3(x+1)) +3
_____
<em>Additional comment</em>
The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.
The horizontal transformations could also be described as ...
- translation right 1/3 unit . . . f(x -1/3)
- reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)
The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.
Answer: a square
Step-by-step explanation:
All of the sides are the same and they are across from each other.