Answer:
Step-by-step explanation:
Answer:
![v(1) = 2\ ft/s](https://tex.z-dn.net/?f=v%281%29%20%3D%202%5C%20ft%2Fs)
Step-by-step explanation:
Given
![s(t) = 4t^2-5t+3](https://tex.z-dn.net/?f=s%28t%29%20%3D%204t%5E2-5t%2B3)
Required
Determine the instantaneous velocity at ![t = 1](https://tex.z-dn.net/?f=t%20%3D%201)
First, we need to determine s(1)
![s(t) = 4t^2-5t+3](https://tex.z-dn.net/?f=s%28t%29%20%3D%204t%5E2-5t%2B3)
![s(1) = 4(1)^2 - 5(1) + 3](https://tex.z-dn.net/?f=s%281%29%20%3D%204%281%29%5E2%20-%205%281%29%20%2B%203)
Evaluate all brackets
![s(1) = 4*1 - 5*1 + 3](https://tex.z-dn.net/?f=s%281%29%20%3D%204%2A1%20-%205%2A1%20%2B%203)
![s(1) = 4 - 5 + 3](https://tex.z-dn.net/?f=s%281%29%20%3D%204%20-%205%20%2B%203)
![s(1) = 2](https://tex.z-dn.net/?f=s%281%29%20%3D%202)
Next; v(t) is calculated as thus;
![v(t) = \frac{s(t)}{t}](https://tex.z-dn.net/?f=v%28t%29%20%3D%20%5Cfrac%7Bs%28t%29%7D%7Bt%7D)
Substitute 1 for t
![v(1) = \frac{s(1)}{1}](https://tex.z-dn.net/?f=v%281%29%20%3D%20%5Cfrac%7Bs%281%29%7D%7B1%7D)
Substitute 2 for s(t)
![v(1) = \frac{2}{1}](https://tex.z-dn.net/?f=v%281%29%20%3D%20%5Cfrac%7B2%7D%7B1%7D)
![v(1) = 2\ ft/s](https://tex.z-dn.net/?f=v%281%29%20%3D%202%5C%20ft%2Fs)
The sum of numbers is = ![1 \frac{19}{30}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B19%7D%7B30%7D)
First find the least common denominator of 1/6, 4/5, and 2/3. The least common denominator of that list is: 30.
= 1/6 + 4/5 + 2/3
= ![\frac{5+24+20}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B5%2B24%2B20%7D%7B30%7D)
= 49 / 30
The sum of numbers in mixed fraction = ![1 \frac{19}{30}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B19%7D%7B30%7D)
<h3>What is mixed fraction?</h3>
A fraction represented with its quotient and remainder is a mixed fraction. For example, 2 1/3 is a mixed fraction, where 2 is the quotient, 1 is the remainder. So, a mixed fraction is a combination of a whole number and a proper fraction.
To learn more about mixed fraction from the given link
brainly.com/question/414559
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We are given the diameter of the circle, I assume. In this case, the formula of the area of the circle is expressed as A = pi d^2/4. where pi is a constant. The only option taht makes sense here is C. 6.25 in2. This should have the constant pi on it.
Answer: 5p - 4
5 times ‘p’ = 5p
4 less than ‘p’ = p - 4
Therefore,
=> 5p - 4