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slavikrds [6]
2 years ago
5

Work out the sum of 1 6 , 4 5 and 2 3 . give your answer as a mixed number in its simplest form.

Mathematics
1 answer:
Tcecarenko [31]2 years ago
6 0

The sum of numbers is = 1 \frac{19}{30}

First find the least common denominator of 1/6, 4/5, and 2/3. The least common denominator of that list is: 30.

= 1/6 + 4/5 + 2/3

= \frac{5+24+20}{30}

= 49 / 30

The sum of numbers in mixed fraction  = 1 \frac{19}{30}

<h3>What is mixed fraction?</h3>

A fraction represented with its quotient and remainder is a mixed fraction. For example, 2 1/3 is a mixed fraction, where 2 is the quotient, 1 is the remainder. So, a mixed fraction is a combination of a whole number and a proper fraction.

To learn more about mixed fraction from the given link

brainly.com/question/414559

#SPJ4

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15% of what number is 234
Alexandra [31]
15% of 1560 is 234. 234/0.15=1560 and 1560 x 0.15=234, therefore the answer is 1560. 
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3 years ago
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Agnes Hammer is a senior majoring in management science. She has been interviewing with several companies for a job when she gra
stiks02 [169]

Answer:

Mean = 30516.67

Standard deviation, s = 3996.55

P(x < 27000) = 0.0011518

Step-by-step explanation:

Given the data:

28500 35500 32600 36000 34000 25700 27500 29000 24600 31500 34500 26800

Mean, xbar = Σx / n = 366200 /12 = 30516.67

Standard deviation, s = [√Σ(x - xbar) / n-1]

Using calculator, s = 3996.55

The ZSCORE = (x - mean) / s/√n

Zscore = (27000 - 30516.67) / (3996.55/√12)

Zscore = - 3516.67 / 1153.7046

Zscore = - 3.048

P(x < 27000) = P(Z < - 3.049) = 0.0011518

3 0
3 years ago
Help! 10 points available
miss Akunina [59]

the answer should be c

8 0
2 years ago
Read 2 more answers
Please help this is due worth 22 points
olga nikolaevna [1]

Answer:

1 is

for 1 disc is $16.50

for 2 disc is $33.00

for 3 disc is $49.50

and

2 is

for 1 book is $6.95

for 2 books is $13.90

for 3 books is $20.85

Step-by-step explanation:

brainliest pls

4 0
2 years ago
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

4 0
3 years ago
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