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Reil [10]
3 years ago
5

Write a program to provide information on the height of a ball thrown straight up into the air. The program should request as in

put the initial height, h feet, and the initial velocity, v feet per second. The height of the ball after t seconds is
Computers and Technology
2 answers:
Ymorist [56]3 years ago
7 0

Answer:

The height of the ball after t seconds is h + vt - 16t 2 feet:

def main():

getInput()

def getInput():

h = int(input("Enter the initial height of the ball: ")) # Adding the int keyword before input() function

v = int(input("Enter the initial velocity of the ball: ")) # Same as above

isValid(h,v)

def isValid(h,v):

if ((h <= 0) or (v <= 0)):

print("Please enter positive values")

getInput()

else:

maxHeight(h,v)

def maxHeight(h,v):

t = (v/32)

maxH = (h + (v*h) - (16*t*t))

print ("\nMax Height of the Ball is: " + str(maxH) + " feet")

ballTime(h, v)

def ballTime(h,v):

t = 0

ballHeight = (h + (v*t) - (16*t*t))

while (ballHeight >= 0):

t += 0.1

ballHeight = (h + (v*t) - (16*t*t))

print ("\nThe ball will hit the ground approximately after " + str(t) + " seconds")

# Driver Code

main()

IgorC [24]3 years ago
4 0

Answer:

I am writing a python code.

def getInput():

   h = int(input("enter the height: "))

   v = int(input("enter the velocity: "))

   isValid(h,v)    

def isValid(h,v):

   if (h<= 0 or v<=0):

       print("not positive ")            

   else:

       height = maximumHeight(h,v)

       print("maximum height of the ball is", height," ft.")

       balltime = ground_time(h,v)

       print("The ball will hit the ground after", balltime, "s approximately.")

def maximumHeight(h,v):

   t = (v/32)

   maxheight = (h + (v*t) - (16*t*t))

   return maxheight    

def ground_time(h,v):

   t = 0.1

   while(True):

       heightofball = (h + (v*t) - (16*t*t))

       if (heightofball <= 0):

           break

       else:

           t += 0.1  

   return t

Explanation:

There are four functions in this program.

getInput() function is used to take input from the user which is height and velocity. h holds  the value of height and v holds the value of velocity. input() function is used to accept values from the user.

isValid() function is called after the user enters the value of height and velocity. This function first checks if the value of height and velocity is less than 0. If it is true the message not positive is displayed. If its false then maximumHeight() is called which returns the maximum height of the ball and function ground_time() is called to return the time when the ball will hit the ground.

maximumHeight() function first divides the value of velocity with 32 as the ball will reach its maximum  height after v/32 seconds. It then returns the maximum height by using the formula:  heightofball = (h + (v*t) - (16*t*t)).

ground_time() calculates the time the ball takes to reach the ground. There is a while loop to height after every 0.1 second and determine when the height is no longer a positive . It uses (h + (v*t) - (16*t*t)) formula to calculate the height and when the value of height gets less than or equal to 0 the loop terminates otherwise it keeps calculating the height while adding 1 to the value of t at each iteration. After the loop breaks, it returns the value of t.

To see the output of the maximum height and time taken by ball to reach the ground, you can call the getInput() function at the end of the above program as:

getInput()

Output:

enter the height: 9

enter the velocity: 10

maximum height of the ball is 10.6525  ft.

the ball will hit the ground after 1.2 s approximately.

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I am writing the program in C++ programming language.  

#include<iostream>  // to use input output functions

using namespace std;   // to identify objects like cin cout

class ProblemSolution {  //class name

private:  

// private data members that only be accessed within ProblemSolution class

int real, imag;

 // private variables for real and imaginary part of complex numbers

public:  

// constructor ProblemSolution() to initialize values of real and imaginary numbers to 0. r is for real part and i for imaginary part of complex number

ProblemSolution(int r = 0, int i =0) {  

real = r; imag = i; }  

/* print() method that displays real and imaginary part in output of the sum of complex numbers */

void print(){  

//prints real and imaginary part of complex number with a space between //them

cout<<real<<" "<<imag;}  

// computes the sum of complex numbers using operator overloading

ProblemSolution operator + (ProblemSolution const &P){  //pass by ref

          ProblemSolution sum;  // object of ProblemSolution

          sum.real = real + P.real;  // adds the real part of the  complex nos.

          sum.imag = imag + P.imag;  //adds imaginary parts of  complex nos.

//returns the resulting object

          return sum;       }  //returns the sum of complex numbers

};   //end of the class ProblemSolution

int main(){    //start of the main() function body

int real,imag;  //declare variables for real and imaginary part of complex nos

//reads values of real and imaginary part of first input complex no.1

cin>>real>>imag;  

//creates object problemSolution1 for first complex number

ProblemSolution problemSolution1(real, imag);  //creates object

//reads values of real and imaginary part of first input complex no.2

cin>>real>>imag;

//creates object problemSolution2 for second complex number

ProblemSolution problemSolution2(real,imag);

//creates object problemSolution2 to store the addition of two complex nos.

ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;

problemSolution3.print();} //calls print() method to display the result of the //sum with real and imaginary part of the sum displayed with a space

Explanation:

The program is well explained in the comments mentioned with each statement of the program. The program has a class named ProblemSolution which has two data members real and imag to hold the values for the real and imaginary parts of the complex number. A default constructor ProblemSolution() which initializes an the objects for complex numbers 1 and 2 automatically when they are created.

ProblemSolution operator + (ProblemSolution const &P) is the operator overloading function. This performs the overloading of a binary operator + operating on two operands. This is used here to add two complex numbers.  In order to use a binary operator one of the operands should be passed as argument to the operator function. Here one argument const &P is passed. This is call by reference. Object sum is created to add the two complex numbers with real and imaginary parts and then the resulting object which is the sum of these two complex numbers is returned.  

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