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3 years ago

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given line passes through the points (-4, -3) and( 4, 1) what is the equation in point slope form of the line that's perpendicul

ar to the given line and passes through the point (-4,3)

2 answers:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

y= -2x-5

Step-by-step explanation:

First find the gradient of the first line

$m = \frac{y2 - y1}{x2 - x1}$

m=

$\frac{1 - - 3}{4 - - 4}$

m=

$\frac{4}{8}$

m=1/2

From this we can find the gradient of the perpendicular line, or the normal.

m1 × m2 = -1

Replace m1 with 1/2

1/2 × m2 = -1

m2= -2

Substitute values into

y-y1=m (x-x1)

y-3=-2 (x+4)

y-3=-2x -8

y=-2x-5

atroni [7]3 years ago

3 0

Answer:

y + 3= one- fourth (x +4

Step-by-step explanation:

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3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

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3 years ago