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madam [21]
2 years ago
8

Beth is going to the State Fair which costs $10 to get in. Each ride costs $5.50. If he has $45 to spend at the Fair, what is th

e greatest number of rides he can ride?​
Mathematics
2 answers:
Jet001 [13]2 years ago
5 0

Answer:same2434..[-

Step-by-step explanation:25790=/,svxy

bonufazy [111]2 years ago
4 0

Answer:

6 rides.

Step-by-step explanation:

We can do subtraction to find out.

Step 1: To get in the fair, he will have to pay $10. (45 - 10 = $35)

Step 2: He wants to get a ride. He will have to pay $5.50. (35 - 5.50 = $29.50)

Step 3: He wants to get a second ride. He will have to pay $5.50. (29.5 - 5.50 = $24)

Step 4: He wants to get a third ride. He will have to pay $5.50. (24 - 5.50 = $18.50)

Step 5: He wants to get a fourth ride. He will have to pay $5.50. (18.50 - 5.50 = $12)

Step 6: He wants to get a fifth ride. He will have to pay $5.50. (12 - 5.50 = $6.5)

Step 7: He wants to get a sixth ride. He will have to pay $5.50. (6.50 - 5.50 = $1)

Step 8: He wants to get a seventh ride, but unfortunately, he doesn't have enough money. So the maximum rides he can get is 6.

Please give me brainliest :)

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The amount invested in the account that yields 7% interest is $4000.

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Please helppp will mark brainlyist with right answer
Len [333]
An angle bisector is a line or ray that divides an angle into two congruent angles
so
in this problem
m∠RST=m∠RSV+m∠VST
m∠RSV=m∠VST
hence
m∠RST=2*m∠RSV --------> equation 1
we have
m∠RST=(6x-24)
m∠RSV=(2x+8)
Substitute in the equation 1
6x-24=2*(2x+8)
6x-24=4x+16
6x-4x=16+24
2x=40
x=40/2
x=20 degrees
therefore
the value of x is 20 degrees
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2 years ago
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