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madam [21]
2 years ago
8

Beth is going to the State Fair which costs $10 to get in. Each ride costs $5.50. If he has $45 to spend at the Fair, what is th

e greatest number of rides he can ride?​
Mathematics
2 answers:
Jet001 [13]2 years ago
5 0

Answer:same2434..[-

Step-by-step explanation:25790=/,svxy

bonufazy [111]2 years ago
4 0

Answer:

6 rides.

Step-by-step explanation:

We can do subtraction to find out.

Step 1: To get in the fair, he will have to pay $10. (45 - 10 = $35)

Step 2: He wants to get a ride. He will have to pay $5.50. (35 - 5.50 = $29.50)

Step 3: He wants to get a second ride. He will have to pay $5.50. (29.5 - 5.50 = $24)

Step 4: He wants to get a third ride. He will have to pay $5.50. (24 - 5.50 = $18.50)

Step 5: He wants to get a fourth ride. He will have to pay $5.50. (18.50 - 5.50 = $12)

Step 6: He wants to get a fifth ride. He will have to pay $5.50. (12 - 5.50 = $6.5)

Step 7: He wants to get a sixth ride. He will have to pay $5.50. (6.50 - 5.50 = $1)

Step 8: He wants to get a seventh ride, but unfortunately, he doesn't have enough money. So the maximum rides he can get is 6.

Please give me brainliest :)

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3 years ago
Read 2 more answers
At 10 percent interest, how long does it take to quadruple your money?
horsena [70]

It takes about 14.55 years for quadruple your money

<em><u>Solution:</u></em>

Given that,

At 10 percent interest, how long does it take to quadruple your money

Rule of 144:

The Rule of 144 will tell you how long it will take an investment to quadruple

Here,

Rate of interest = 10 %

Therefore, number of years to quadruple your money is obtained by dividing 144 by 10

<em><u>Rule of 144 Formula: </u></em>

N = \frac{144}{R}

Where:

N = Number of many years times.

144 = Is the constant variable.

R = Rate of interest.

\rightarrow N =  \frac{144}{10} = 14.4

Thus it takes about 14.4 years for quadruple your money.

<em><u>Another method:</u></em>

If initial amount is $ 1 and it if quadruples it should be $ 4

We have to find the number of years if rate of interest is 10 %

Let "n" be the number of years

Then we can say,

Amount = Principal(1+\frac{R}{100})^n

4 = 1(1+\frac{10}{100})^n

4 = 1(1+0.1)^n\\\\4= 1(1.1)^n\\\\4 = 1.1^n\\\\We\ know\ that,\\\\(1.1)^{14.55} = 1.1^n\\\\We\ know\ that\\\\If\ a^m = a^n\ then\ m = n\\\\Therefore,\\\\14.55 = n\\\\n = 14.55

Thus Option D 14.55 years is correct

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