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3 years ago

What is the formula for a counterclockwise rotation of 180°?!?!

2 answers:

7 0

Answer: A (x,y) is your original. Your answer after would be A' (-x,-y) you would change the sign. If its negative it becomes positive, and if it'd positive it becomes negative.

siniylev [52]3 years ago

3 0

Answer: you change both signs to the opposite

Step-by-step explanation:

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A basketball court is in the shape of a rectangle. It has a length of (x − 7) meters and a width of (x + 3) meters. The expressi

Step2247 [10]

X^2 -3x+7x-21

so simplified is:

x^2 - 4x - 21

5 0

3 years ago

I need help with this question, I can work out the ratio but I am just confused with the question. So do help if you can please.

nirvana33 [79]

Answer:

76%

Step-by-step explanation:

So basically 528 represents a full circle and the amount in the circle is 2:5 to that in the stalls.

So you divide 528 by 2 and then multiply it by 5 to get a full stall of 1320

you then add 1320 and 528 to get a full theater of 1848

to get 2/3 of seats in the stall you divide 1320 by 3 and then multiply it by 2 to get 880.

For 2/3 of the stall and a full circle you add 880 and 528 to get 1408.

You divide the amount of people in the theater on Friday by the total amount of people which the theater can hold so 1408 divided by 1848 and you get the percentage of 76%

8 0

3 years ago

Helpppppp me plzzzzzzzzzz

lawyer [7]

Answer:

21/4 or 5.25

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$