Answer:
15.12
Step-by-step explanation:
3.6 x 4.2
first aline the decmials like you would regularly do to multiply.
Then multiply 2 x 6=12 and then 2 x 3=6 and put them down were you would already do noramly multiplying.
and then muliply 4x6=24 and 4x3=12 and do the same thing as you would do normaly and then add 72 and 144 to get 1512 and then count your decmail placing. which is 2 placeing in total which makes 1512 into 15.12
and now you done!
Example of how it should look...
3 . 6
× 4 . 2
+ 7 . 2
+ 1 4 4
= 1 5 1 2
144 ways because 12 songs 12 ways 12*12
Answer:
Step-by-step explanation:
Your answer would be 80% or a B
The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
Answer: ![\dfrac{2}{9}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B9%7D)
Step-by-step explanation:
Given
The spinner has 6 equal sections A, B, C, D, E, and F
The two events occurred one after the other. So, the probability is the product of the probabilities of each event.
There are two consonants in the given 6 letter
The probability of landing over a consonant is
![P_1=\dfrac{2}{6}](https://tex.z-dn.net/?f=P_1%3D%5Cdfrac%7B2%7D%7B6%7D)
The number greater than 2 in a cube are 3,4,5,6
So, probability corresponding to it
![P_2=\dfrac{4}{6}](https://tex.z-dn.net/?f=P_2%3D%5Cdfrac%7B4%7D%7B6%7D)
So, the required probability is
![\Rightarrow P=P_1\times P_2\\\Rightarrow P=\dfrac{2}{6}\times \dfrac{4}{6}\\\\\Rightarrow P=\dfrac{8}{36}\\\\\Rightarrow P=\dfrac{2}{9}](https://tex.z-dn.net/?f=%5CRightarrow%20P%3DP_1%5Ctimes%20P_2%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B2%7D%7B6%7D%5Ctimes%20%5Cdfrac%7B4%7D%7B6%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B8%7D%7B36%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B2%7D%7B9%7D)