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Umnica [9.8K]
4 years ago
12

What is the volume of each cone​

Mathematics
1 answer:
Viefleur [7K]4 years ago
3 0
1) about 29.32
2) about 235.62
3) about 410.5
4) about 74220.13
5) about 366.52
6) about 1268.2
7) about 320.44
8) about 19.27
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Vlad1618 [11]

Answer:

2

Step-by-step explanation:

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6 0
3 years ago
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Can you please help me solve this question ?
Ronch [10]

Answer:

(4,5).

Step-by-step explanation:

The solution to a system of equations that is graphed is when the two lines intersect. They intersect at (4,5), so the solution to the system is (4,5). Hope this helps!

7 0
4 years ago
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Please answer and explain the answer
Nady [450]

Well every year it grows 8 inches which means that for every one year it grows 8 inches.

BUT, the tree started out 14 inches so every year you have to add the original 14 inches.

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h=8a+14

Hope this helps :)


5 0
4 years ago
The sum of Mary and Al's age is 48. Twelve years ago, Mary was twice as old as Al.
QveST [7]
Let us denote the years of Mary with M and the years that Al have with A.
<span>We know that the sum of Mary and Al's age is 48. So, we can write:
M+A=48 (1)
</span><span>We also know that twelve years ago, Mary was twice as old as Al. So we can write:
M-12=2*A (2)
From the first equation (1): M=48-A
Let put this in the second equation:
48-A-12=2A
36=3A
A=12
M=48-12=36
</span>
8 0
3 years ago
Consider the following sample set of scores. Assume these scores are from a discrete distribution. 21 29 32 38 38 45 50 64 72 10
ASHA 777 [7]

Answer:

Original data: 21 29 32 38 38 45 50 64 72 100

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

Mode =38.

Median = \frac{38+45}{2}=41.5

Change 1: 2 29 32 38 38 45 50 64 72 100

\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47

Mode =38.

Median = \frac{38+45}{2}=41.5

Change 2: 29 32 38 38 45 50 64 72 100

\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52

Mode =38.

Median = 45

Step-by-step explanation:

Original data: 21 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{10} X_i}{10}

And if we replace we got:

\bar X = \frac{21+29+32+38+38+45+50+64+72+100}{10}=48.9

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

Change 1: 2 29 32 38 38 45 50 64 72 100

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{10} X_i}{10}

And if we replace we got:

\bar X = \frac{2+29+32+38+38+45+50+64+72+100}{10}=47

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have an even number of points the median is calculated as the average between the observations 5 and 6 from the dataset ordered.

Median = \frac{38+45}{2}=41.5

Change 2: 29 32 38 38 45 50 64 72 100

Now the sample size is 9 instead of 10

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{9} X_i}{9}

And if we replace we got:

\bar X = \frac{29+32+38+38+45+50+64+72+100}{9}=52

The mode is the most repeated value in the sample and on this case is Mode =38.

Since we have odd number of points the median is calculated from the 5 position of the dataset ordered.

Median = 45

7 0
4 years ago
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