(0,-6), (6, -3), and (6,-6)
If you plot them on a graph there are only two point options (in green and purple) since it's a right triangle but you have to use the one that has -6 as the y value
Answer:
Step-by-step explanation:
Rewrite this quadratic in standard form: 3x^2 + 7x - 1.
The coefficients of x are {3, 7, -1}, and so the discriminant is b^2 - 4ac, or
7^2 - 4(3)(-1), or 49 + 12, or 61. Because the discriminant is positive, this quadratic has two real, unequal roots
First, square both sides. This will cancel out the radical.

(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6