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kumpel [21]
3 years ago
6

In the diagram below, line t intersects parallel lines r and s.

Mathematics
2 answers:
Gnoma [55]3 years ago
5 0
$2$2$$2$272jwuiwiwiwiw
Lelu [443]3 years ago
3 0

Answer:

112

Step-by-step explanation:

Supplementary Angle Theorem

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Write and simplify an expression for the perimeter of each figure
DedPeter [7]

Answer:

4d + 6c - 6

Step-by-step explanation:

The perimeter of the rectangle is the sum of all 4 sides

perimeter = 2d - 3 + 3c + 2d - 3 + 3c = 4d + 6c - 6


7 0
3 years ago
Read 2 more answers
Find the surface area of the prism. A solid with six rectangular faces that has length 5 inches, width 3 inches, and height 7 in
True [87]

Answer:

290in

Step-by-step explanation:

3 0
3 years ago
Help please!!<br> .<br> .<br> .<br><br> .
rjkz [21]

Answer:

2nd Triangle:

1st line: Given, but if you were given that JK and MP were parallel, you'd use the phrase "If 2 parallel lines are cut by a transversal, alternate interior angles are congruent".

2nd line: Given. If you were given something like "JP bisects KM, or "JP and KM bisect each other", you'd write "bisectors cut lines equally in half".

3rd line: Vertical angles are congruent. Angles opposite each other (like JLK and MLP are vertical and always congruent.

4th line: SAS (or side angle side) You have an angle, a side, and an angle all in order. Therefore it's SAS.

Show me the full screenshots of the other 2 and I'll happily solve them.

3 0
3 years ago
Help me please please
Nastasia [14]

Answer:

A

Step-by-step explanation:

slope=3-(-9)/-4-5

= 12/-9=4/-3

so A

5 0
3 years ago
The standard normal distribution is most completely described as a: A. distribution that exhibits zero skewness and no excess ku
Kaylis [27]

Answer:

A. distribution that exhibits zero skewness and no excess kurtosis.

Correct. We know that the skewness for a normal distribution is zero, since for any symmetric distributio we need to have a skewness near zero, since this measure represent the assymetry of the data.

And the will not have excess of kurtosis for this distribution since the kurtosis measures the extreme values and for this case in the normal distribution we don't expect the outliers with high frequency.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

And this distribution is described by two parameters. The first one is the mean given by \mu and is a measure of central tendency. And the seconde parameter is the deviation given by \sigma.

And with this two parameters we say that if X follows a normal distribution then:

X \sim N(\mu, \sigma)

Let's analyze one by one the options:

A. distribution that exhibits zero skewness and no excess kurtosis.

Correct. We know that the skewness for a normal distribution is zero, since for any symmetric distributio we need to have a skewness near zero, since this measure represent the assymetry of the data.

And the will not have excess of kurtosis for this distribution since the kurtosis measures the extreme values and for this case in the normal distribution we don't expect the outliers with high frequency.

B. normal distribution with a mean of zero and a standard deviation of one.

False. For this case this distribution is a particular case of the normal distribution and is known as the normal standard distribution but the mean is not always equal to 0 and the deviation =1 for any normal distributon.

C. symmetrical distribution with a mean equal to its median.

False. This statement is true but we don't have the mode incoroporate on this definition. Since in the normal distribution we have:

Mean = Median = Mode

So for this reason is not the most complete answer for this case.

5 0
3 years ago
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