To find the area of a square you multiply length x width or side x side.
So... 0.2x0.2 = 0.04; b^3 x b^3 = b^6 and m^4 x m^4 = m^8;
Putting everything back together you get.....0.04 b^6m^8
Answer:
1. 1/2 +/-√5
2. 1 +/- i √6/2.
Step-by-step explanation:
1. f(x) = 4x^2 - 8x - 1
x = [-(-8) +/-√((-8)^2 - 4*4*-1)] / (2*4)
x =[ 8 +/- √80] / 8
= 1 +/- 4√5/8
= 1 +/- √5/2
= 1/2 +/-√5
2. By a similar method the zeros of the the second equation are:
x = [-(-4) +/- √((-4)^2 - 4*2*5)] / 4
= 4 +/- √(16 - 40) / 4
= 1 +/- √(-24)/4
= 1 +/- i √6 * 2 / 4
= 1 +/- i √6/2.
The symbol is the electric current that is inputted into the circuit.
Here, m³ n⁻⁶ p⁰
It would be: m³ / n⁶ * 1 [ As p⁰ = 1 ]
In short, Your Answer would be: m³/n⁶
Hope this helps!