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Vlad1618 [11]
3 years ago
8

75 Points If You get This Right

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0

Answer:

1.   2

2.  6

3.  2

4.  3

5.  1

6.   1

Step-by-step explanation:

First put the data in order from smallest to largest

2,2,2,3,3,6

The minimum is 2

The maximum is 6

The median is 2,2,2    ,3,3,6  is between the 2 and 3  (2+3)/2 = 2.5

The 1st quartile is 2,2,2  is the middle number   = 2

The third quartile is   3,3,6  is the middle number is 3

The interquartile range is 3-2 =1

The mean average deviation is

First find the mean: ( 2+2+2+3+3+6)/6 =18/6 = 3

Then find how far each point is from the mean

(3-2) + (3-2) + (3-2) + (3-3) + (3-3) + (6-3)  = 6

Divide this by the number of data points

6/6 =1

maw [93]3 years ago
5 0

Answer:

\Large \boxed{1. \ 2} \\ \\ \Large \boxed{2. \ 6} \\\\ \Large \boxed{3. \ 2} \\\\ \Large \boxed{4. \ 3} \\\\ \Large \boxed{5. \ 1} \\\\ \Large \boxed{6. \ 1}

Step-by-step explanation:

The minimum value of the data set is the lowest value in the data set.

<u>2</u>, 2, 2, 3, 3, 6

2 is the lowest value. 2 is the minimum value of the data set.

The maximum value of the data set is the highest value in the data set.

2, 2, 2, 3, 3, <u>6</u>

6 is the highest value. 6 is the maximum value of the data set.

The first quartile of the data set is <u>2, 2, 2</u>, the middle value is 2.

The third quartile of the data set is <u>3, 3, 6</u>, the middle value is 3.

The interquartile range of the data set is:

\sf IQR=Q_3-Q_1 = 3-2=1

The mean average deviation from the mean is:

\sf \displaystyle m \ (mean)=\frac{sum \ of \ terms}{number \ of \ terms} = \frac{2+2+2+3+3+6}{6} =\frac{18}{6} =3

\sf \displaystyle mean \ average \ deviation = \frac{(m-x_1)+(m-x_2)...}{number \ of \ terms}

\sf \displaystyle \frac{(3-2)+(3-2)+(3-2)+(3-3)+(3-3)+(6-3)}{6}=\frac{6}{6} =1

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