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san4es73 [151]
3 years ago
14

Find the Quotient. please help me 4)5,389

Mathematics
1 answer:
Ahat [919]3 years ago
4 0
The answer is 1347.25

Have a nice day :)
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Find the measure of the angle indicated. Assume that lines which appear tangent are tangent.
Tanzania [10]

Answer:

D. 69°

Step-by-step explanation:

I think you divide 222° by 2, which equals 111, then subtract that from 180°, which equals 69°.

3 0
3 years ago
At which values of x does the function F(x) have a vertical asymptote? <br> F(x)=1/x(x+6)(x-1)
Morgarella [4.7K]
Answer:
X=0
X=-6
X=1
Explanation: set the denominator equal to zero and solve for x
4 0
3 years ago
A taxi service charges a flat fee of $1.25 and $0.75 per mile. If Henri has $14.00, which of the following shows the number of m
maks197457 [2]
 1.25 + 0.75x = 14
Solving for x gives the answer of 17. Thus, Henri can afford to travel 17 miles.
7 0
3 years ago
A gardener brought 5 rabbits, after 2 months rabbits became 10, and after 4 months they became 20. If the growth continues on th
Natali [406]

Answer:

<em>The amount of rabbit after 1 year will be </em><em>320</em><em>.</em>

Step-by-step explanation:

A gardener brought 5 rabbits, after 2 months rabbits became 10.

The growth continues on the same ratio.

This represents a geometric sequence with 1st term as 5 and common ratio as 2.

As we have to find the amount of rabbit after 1 year, so the we have to find \dfrac{12}{2}+1=6+1=7th term. As the time difference between each counting is 2 months, so we divided 1 year or 12 months of time by 2.

nth term in a G.P is,

T_n = ar^{n-1}

Putting the values,

T_7 = 5\times (2)^{7-1}=5\times 2^6=320

3 0
3 years ago
Read 2 more answers
Write the point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 include all of you
ycow [4]

<u>Answer: </u>

The point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 is 3x + y – 19 = 0

<u>Solution: </u>

The point slope form of the line that passes through the points \left(x_{1} y_{1}\right) and parallel to the line with slope “m” is given as  

y - y_{1} = m\left(x - x_{1}\right) --- eqn 1

Where “m” is the slope of the line. x_{1} \text { and } y_{1}are the points that passes through the line.

From question, given that slope “m” = -3

Given that the line passes through the points (6,1).Hence we get x_{1} = 6 ; y_{1} = 1

By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -3 can be found out.

y – 1 = -3(x – 6)

y – 1 = -3x +18

On rearranging the terms, we get

3x + y -1 – 18 = 0

3x + y – 19 = 0

Hence the point slope form of given line is 3x + y – 19 = 0

8 0
3 years ago
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