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Oduvanchick [21]
3 years ago
14

How will the graph change if the car fee is changed to 10 dollars?

Mathematics
1 answer:
defon3 years ago
6 0

Answer:

if you add more money

Step-by-step explanation:

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A<br> 9<br> Kylie drives 291 miles in 6 hours.<br> (a) What is her average speed?
ivolga24 [154]

Answer:

48.5 m/s

Step-by-step explanation:

291/6 = 48.5

5 0
3 years ago
Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha
raketka [301]

According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0
1 year ago
PLEASE HELP ASAP!!!
Elan Coil [88]

Answer:

The number is 5

Step-by-step explanation:

6+3n = 5n-4

Subtract 3n from each side

6+3n-3n = 5n-3n-4

6 = 2n-4

Add 4 to each side

6+4 = 2n-4+4

10= 2n

Divide by 2

10/2 =2n/2

5=n

6 0
4 years ago
Help please it’s due hella soon also please leave a small explanation
murzikaleks [220]
1) y=3x-4
When x increases by 1, y increases by 3 so the slope is rise/run → 3
y-int is -4 bc y-value is -4 when x=0

2)y=-3x+4
When x increase by 2, y decreases by 6 so the slope is rise/run → -3
y-int is 4 bc y-value is 4 when x=0

3)y=-1/3x+4
When x increase by 3, y decreases by 1 so the slope is rise/run → -1/3
y-int is 4 bc you now have the equation y=-1/3x+b and u just have to plug in random point from the graph, so ex, 6 into x and 2 into y. You can get 4 as b in the equation.

4)y=1/3x-4
When x increases by 6, y decreases by 2 so the slope is rise/run → 1/3
y-int is -4 bc u do the same thing as 3)
For ex, plug in 6 for x and -2 for y and you can get -4 as the b in the equation.
6 0
4 years ago
I need step by step explanation and answer please
fredd [130]

Answer:

2

Step-by-step explanation:

Trigonometric identities:

\sin^{2} (x)  +  { \cos}^{2} (x) = 1 \\  {\cos}^{2} (x) = 1 -  { \sin}^{2} (x) \\   { \sin }^{2} x = 1 - {\cos}^{2} (x) \:

Replace into the equation

\frac{ \sqrt{1 -  \cos^{2} (x) } }{ \sin(x) }  +  \frac{ \sqrt{1 -  \sin^{2}(x) } }{ \cos(x) }   \\ \\   =  \frac{ \sqrt{ \sin^{2}(x) } }{ \sin(x) }  +  \frac{ \sqrt{ \cos^{2}(x) } }{ \cos(x) }

Remove roots and simply

=  \frac{ \sin(x) }{ \sin(x) }  +   \frac{ \cos(x) }{ \cos(x) }  \\  \\  = 1 + 1 \\  = 2

7 0
3 years ago
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