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MariettaO [177]
3 years ago
10

Find the value of X to find measurement of

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

Value of angle A is 83.

solution,

I) x°+x°+15+2x°+1=180(Sum of angle of triangle)

or,4x+16=180

or,4x=180-16

or x=164/4

.°.x=41

Again

Angle A = 2x°+1 = 2×41 + 1 =83.

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Please help I’m stuck
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90<-30p+15 how do you solve this
Alenkinab [10]

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56.72 centiliters equals how many decaliters?​
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6 0
3 years ago
A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla
nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = P(A)= \frac{13}{100}=0.13

The probability that athlete is a basketball player = P(B)= \frac{52}{100}=0.52

The probability that athlete is both basket ball player and  football player = P(A\cap B) = \frac{9}{100}=0.09

We have to find the probability that an athlete chosen is either a football player or a basketball player P(A\cup B).

Now we know that;

P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0
4 years ago
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