Question

A rectangular pyramid has a base measuring 4 in. on each side and an altitude of 6 in. What is its volume? cubic inches

Answer 1

The answer is 32.
you use the formula (1/3) b^2 h.
so you would have 4^2 which is 16. 16x6= 96.
96x.33= 31.68
round up its 32

Answer 2

Answer:

$V=512in^3$

Step-by-step explanation:

A rectangular pyramid is a polyhedron whose surface is formed by a base that is a rectangle and triangular side faces that converge on a vertex called the apex. The volume of a rectangular pyramid is given by:

$V=\frac{1}{3} *b^2*h$

Where:

$b=Area\hspace{3}of\hspace{3}the\hspace{3}base\\h=Pyramid\hspace{3}height$

The problem tell us that on each side the base has a length of 4 in, therefore, the area of the base is:

$b=4*4=16in$

The problem also tell us that:

$h=6in$

So, replacing the previous data in the volume equation:

$V=\frac{1}{3} *(16)^{2}*6=\frac{256*6}{3} =\frac{1536}{3} =512in^3$