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maks197457 [2]
2 years ago
7

what a self improvement for a busy person who had difficulty finding time to exercise/ dropping out of clubs and activities/ Ref

using social invitations from friends/ scheduling daily invitation activity/ sleeping fewer hours at night
Health
1 answer:
timama [110]2 years ago
3 0

Hi !

What a self improvement for a busy person who had difficulty finding time to exercise ?

<em>-  scheduling daily invitation activity</em>

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romanna [79]

Explanation:

A hypergeometric distribution as a function of statistical distribution where members from two groups are analysed,  without replacing those members. Unlike binomial distributions, in which the probability remains the same for each trial, in hypergeometric distributions, these members are not replaced- each trial's probability affects the probability within next trial.

This is used in the process of random sampling and as a means of quality control in statistics; for example selecting members of a sports team from a mixed population of boys and girls.

Hypergeometric Formula..,

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∴ hypergeometric probability is:

h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]

this distribution always has... 

  • its mean=  n * k / N .
  • its variance  is n * k * ( N - k ) * ( N - n ) /  [ N2 * ( N - 1 ) ] .

Thus….

Total number of bottles =  22

Number of contaminated bottles = 6

Number of tested bottles = 4

X= a random variable representing the number of contaminated bottles selected for the test.

N = 22

K = 6

n = 4

The probability mass function, f(x), is given by...

P(X=x)) = [ kCx] [ N-kCn-x ] / [ NCn ]    x= 0,1,2,3,...,n

           = \frac{[6 C 1] [22-6 C 4-1]}{[22 C 4]}

OR          

\frac{C\left \ {{k=6} \atop {x=1}} \right.   C\left \ {{22-6} \atop {4-1}} \right. }{C \left \ {22} \atop {4}} \right. }

Cxk= C14= 4!(1!(4 - 1)!)^{-1}= 24(6)^{-1}= 4\\Cn-xN-k=C\left \ {{22-6} \atop {4-1}} \right. } =16!(4!(16-4)!)^{-1}\\(CnN)^{-1}=(C \left \ {{y=22} \atop {x=6}} \right. ) ^{-1}=[22!(6!(22-6)!)^{-1}]^{-1}

f(x)= p= P(X=1)=0.45933014354067

P(that more than 1 of the tested bottles is contaminated);

P(X>1)=1−P(X≤1)=1−(P(X=0)+P(X=2))

                P(X>1)=0.291866028708134

Probability that one is contaminated: 0.4593(4 dec places)

Probability that more than one is contaminated: 0.2919 (4 dec places)

Learn more about calculating probability at brainly.com/question/4021035

Learn more about calculating event probability at brainly.com/question/6649771

#LearnWithBrainly

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Weight of an object in air​
ExtremeBDS [4]

Answer:

Weight of an object in air is 25 N

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