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vivado [14]
3 years ago
8

Which choice is the equation of a line that passes through the point (–6, –2) and is perpendicular to the line represented by th

is equation?
y = −3x + 1

A. 3x + y = 1
B. y = 1/3x
C. y = −3x
D. −3y = −x + 1
Mathematics
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

  B.  y = 1/3x

Step-by-step explanation:

The slope of the given line is -3, so the slope of the perpendicular line will be the negative reciprocal of that: -1/(-3) = 1/3. This eliminates choices A and C.

We can find the y-intercept (b) if we use the given point values in the equation ...

  y = 1/3x +b

we get ...

  -2 = (1/3)(-6) +b

  -2 = -2 +b . . . simplify

  0 = b . . . . . . . add 2

So, the equation of the perpendicular line through the given point is ...

  y = 1/3x . . . . matches choice B

_____

<em>Alternate solution method</em>

You can try the given point in the given equations. You will find that only the equation of choice B will work.

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3 years ago
Read 2 more answers
Help with this please
aliina [53]
AB = 6 cm, AC = 12 cm, CD = ?

In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.

Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°

In order to find ∠BCA, use the law of sines:
 
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA

Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°

Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°

In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.

12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
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3 years ago
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