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marusya05 [52]
3 years ago
13

How do I go about to understand the problem

Mathematics
1 answer:
raketka [301]3 years ago
6 0
You just have to multiply the numerators and the denominators.
The answer is 14 over 56. Then, you need to simplify the question.
So, since 56 is divisible by 14, divide the numerator and the denominator by 14.
Then you get your answer, which is one-fourth.
Hope that helped!
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The table shows results of an experiment that was replicated.
KiRa [710]

The option that best describes the experiment is accurate and reproducible.

<h3>What option describes the data?</h3>

All the values from the experiment are close in value to the accepted value. This indicates that the experiment is accurate. Two experiments yield the same values. This indicates that the experiment is reproducible.

Here is the table used in answering the question:

Accepted Value: 130

Experiment 1 129

Experiment 2 131

Experiment 3 129

Experiment 4 132

To learn more about experiments, please check: brainly.com/question/14019529

#SPJ1

4 0
2 years ago
Selma is buying a cell phone for business. The regular price of the phone is $179. If she buys the phone at 20% discount how muc
Nuetrik [128]

Answer:

\large \boxed{\$35.80}  

Step-by-step explanation:

Discount = Regular price × % discount

\text{Discount} = \text{\$179 regular price} \times \dfrac{\text{\$20 }}{\text{\$100 regular price}} = \textbf{\$35.80}\\\text{Selma will save $\large \boxed{\mathbf{\$35.80}}$}

4 0
3 years ago
For a Saturday matinee, adult tickets cost $8.50 and kids under 12 pay only $7.00. If 80 tickets are sold for a total
jolli1 [7]

Answer:

  • 30 adult tickets,
  • 50 kids tickets

Step-by-step explanation:

<u>Given</u>

  • Cost of adult ticket = $8.50
  • Cost of kids ticket = $7.00
  • Number of tickets = 80
  • Total cost = $605

Let the adult ticket be a and kids be k

<u>We got equations</u>

  • a + k = 80
  • 8.5a + 7k = 605

<u>From the first equation we get</u>

  • k = 80 -a

<u>Substituting k in the second equation</u>

  • 8.5a + 7(80 - a) = 605
  • 8.5a - 7a + 560= 605
  • 1.5a = 45
  • a = 45/1.5
  • a = 30

<u>Then finding k</u>

  • k = 80 - 30 = 50

8 0
3 years ago
F(x) = 9-3x<br> g(x) = 5x-7<br> Find f(x)+g(x).
Bezzdna [24]

Answer:

In the problem, the sum of the two functions is 2x + 2

Step-by-step explanation:

For this problem, we have to add together f(x) and g(x).

<em>f(x) = 9 - 3x</em>

<em>g(x) = 5x - 7</em>

(f + g)(x) = (9 - 3x) + (5x - 7)

Combine like terms.

(f + g)(x) = 2x + 2

So, when you combine the two functions together, you will get 2x + 2.

8 0
3 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
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