To calculate for the magnitude of vector PQ, what needs to be done is to determine the distance between them through the two-point equation which is shown below.
d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)
Substituting the known values,
d = sqrt ((13 - 5)² + (12 - 9)²)
The value of d from the equation is sqrt of 73 or 8.54.
Therefore, the magnitude of the vector is equal to 8.54.
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Answer:
Maximum
Step-by-step explanation:
dy/dx = 4 - 4x³ = 0
x³ = 1
x = 1
y = 4 - 1 = 3
There's only one stationary point: (1,3)
Nature:
d²y/dx² = -12x²
x = 1, so -12
Negative means it's maximum turning point
Answer: The first graph is the right graph according to the given situation.
Step-by-step explanation:
Given: Becky created a graph to represent her distance away from home one afternoon.
She left home and ran to the park⇒ She started running from zero distance from the home .⇒the second and fourth graphs are wrong .
After that she met some friends and stayed at the park, then walked back home using the same route.⇒ The first one is correct because there we can see the graph is parallel to time axis for a interval but in the third one it shows that she she hasn't took rest .
The answer would be 410 hope this helps