Hey there!

Anything to the power of 0 is 1. So that means x can be equal to any number. Let's say 1^0, it will still equal 1. 2^0 is also equal to 1. X is therefore not a number since it can be anything.

Hope this helps!

Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
__
For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
__
For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
___
If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
_____
Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
The solution to the inequality is that Mikey's family can drive at most 148
Inequality shows the non equal comparison of numbers or expressions.
Given that Mikey situation can be represented by the inequality:
112 + x ≤ 260
Solving the inequality:
112 + x ≤ 260
Subtract 112 from both sides of the equation:
112 + x - 112 ≤ 260 - 112
x ≤ 148
Hence from the inequality, we can see that Mikey's family can drive
at most 148
Find out more at: brainly.com/question/25285332
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=

0=x^2+12x+16
a=1
b=12
c=16
x=

x=

x=

x=

x=

x=

or

aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721