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CaHeK987 [17]
3 years ago
6

Help. What is the slope.

Mathematics
1 answer:
My name is Ann [436]3 years ago
3 0
Answers: choice C) -4

----------------------------------------------------------
----------------------------------------------------------

Explanation:

There are two basic ways to find the slope. 
-----------------------------------
The first way is where we use the slope formula
m = (y2-y1)/(x2-x1)
The two points are (x1,y1) = (-1,8) and (x2,y2) = (2,-4)
Plug the coordinate of those points into the slope formula, then simplify
m = (y2-y1)/(x2-x1)
m = (-4-8)/(2-(-1))
m = (-4-8)/(2+1)
m = (-12)/(3)
m = -4

The slope is -4

-----------------------------------
The second way is to use a more visually oriented approach.
Start at (-1,8). 
Draw a straight vertical line through this point. Then move to the point (2,-4) and draw a completely flat horizontal line through this point. 
Mark the intersection between these two lines (vertical and horizontal) as point A

Now go back to (-1,8). Count the number of spaces you must move down to go from (-1,8) to point A. You should count out 12 spaces. This is the run, which in this case is negative since we're going downhill as we move from left to right

Then count 3 spaces to go from point A to (2,-4). This is the run

Rise = -12
Run = 3
Slope = Rise/Run = -12/3 = -4

As you can probably see, this effectively mirrors some parts of the slope formula above

No matter which method you use, the slope is -4

-4 is the same as -4/1

A slope of -4/1 means we go down 4 units and then move to the right 1 unit

So that means rise/run = -12/3 is the same as saying rise/run = -4/1

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<img src="https://tex.z-dn.net/?f=4x%20%2B%203y%20%3D%200%20%5C%5C5y%20%2B%2053%20%3D%2011x%20%5C%5C%20" id="TexFormula1" title=
Anvisha [2.4K]

Answer:

x = 3, y = -4

Step-by-step explanation by substitution:

Solve the following system:

{4 x + 3 y = 0 | (equation 1)

5 y + 53 = 11 x | (equation 2)

Express the system in standard form:

{4 x + 3 y = 0 | (equation 1)

-(11 x) + 5 y = -53 | (equation 2)

Swap equation 1 with equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

4 x + 3 y = 0 | (equation 2)

Add 4/11 × (equation 1) to equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+(53 y)/11 = -212/11 | (equation 2)

Multiply equation 2 by 11/53:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(11 x)+0 y = -33 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -11:

{x+0 y = 3 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer: {x = 3 , y = -4

_____________________________________

Solve the following system:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Isolate terms with x to the left hand side.

Subtract 3 y from both sides:

{4 x = -3 y

5 y + 53 = 11 x

Hint: | Solve for x.

Divide both sides by 4:

{x = -(3 y)/4

5 y + 53 = 11 x

Hint: | Perform a substitution.

Substitute x = -(3 y)/4 into the second equation:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for y:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Isolate y to the left hand side.

Subtract 53 - (33 y)/4 from both sides:

{x = -(3 y)/4

(53 y)/4 = -53

Hint: | Solve for y.

Multiply both sides by 4/53:

{x = -(3 y)/4

y = -4

Hint: | Perform a back substitution.

Substitute y = -4 into the first equation:

Answer: {x = 3 , y = -4

7 0
3 years ago
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