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3 years ago

If (a^3+27)=(a+3)(a^2+ma+9) then m equals

Mathematics

1 answer:

Ronch [10]3 years ago

7 0

Answer:

m = - 3

Step-by-step explanation:

a³ + 27 ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

a³ + 27

= a³ + 3³

= (a + 3)(a² - 3a + 9)

comparing a² - 3a + 9 to a² + ma + 9, then

m = - 3

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Write as a product 27a^3−(a−b)^3

jarptica [38.1K]

Answer:

(2a +b)·(13a^2 -5ab +b^2)

Step-by-step explanation:

The factorization of the difference of cubes is a standard form:

(p -q)^3 = (p -q)(p^2 +pq +q^2)

Here, you have ...

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so the factorization is ...

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3 years ago

What is the equation of the line that passes through the point 3,-1 and has a slope of 2

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Answer:

y=2x-7

Step-by-step explanation:

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2 years ago

What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

Solution:

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

Step 1: GCF of 44, 22 and 11

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

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3 years ago

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Answer:

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Step-by-step explanation:

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