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3 years ago

A study was done to compare people's religion with how many days that they have said they have been calm in the past three days.

Mathematics

1 answer:

umka21 [38]3 years ago

6 0

Answer:

0.061

Step-by-step explanation:

Number of days Protestants

0 50

1 27

2 6

3 16

The proportion of protestant remain calm for 2 days= number of protestant calm for 2 days/ Total number of protestant calm for 0-3 days

The proportion of protestant remain calm for 2 days =6/50+27+6+16=6/99=0.061 (rounded to 3 decimal places)

Thus, 6.1% of protestant remain calm for 2 days.

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If you are paid $2.20 an hour, worked for 26 hours this

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Step-by-step explanation:

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A linear function has a slope of 7, and when x is 3, the value for y is 22. Use a graph or a table to figure out the equation of

Alex787 [66]

When you are given a point (x1,y1) and slope m the equation is
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Suppose that x is a binomial random variable with n=5, p=. 3,and q=. 7.1. Write the binomial formula for this situation and list

Radda [10]

Answer:

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: Any from 0 to 5.

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 5, p = 0.3, q = 1 - p = 0.7$

$P(X = x) = C_{5,x}.(0.3)^{x}.(0.7)^{5-x}$

Possible values of x: 5 trials, so any value from 0 to 5.

For each value of x calculate p(☓ =x)

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.3)^{0}.(0.7)^{5-0} = 0.16807$

$P(X = 1) = C_{5,1}.(0.3)^{1}.(0.7)^{5-1} = 0.36015$

$P(X = 2) = C_{5,2}.(0.3)^{2}.(0.7)^{5-2} = 0.3087$

$P(X = 3) = C_{5,3}.(0.3)^{3}.(0.7)^{5-3} = 0.1323$

$P(X = 4) = C_{5,4}.(0.3)^{4}.(0.7)^{5-4} = 0.02835$

$P(X = 5) = C_{5,5}.(0.3)^{5}.(0.7)^{5-5} = 0.00243$

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4 years ago

Question

nata0808 [166]

Answer:5x

Step-by-step explanation:

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4 years ago

Explain how to write 50,000 using exponents

Zinaida [17]

5 x 10 = 5x10¹ = 50
5 x 100 = 5x10² = 500
5 x 1000 = 5x10³ = 5000

5 x 10,000 = 5x10⁴ = 50,000

4 0

4 years ago