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Alona [7]
2 years ago
13

Combining like terms 6w+9w-4

Mathematics
2 answers:
mr Goodwill [35]2 years ago
7 0
Since 6w and 9w both are the same you add them, making it 15w; then just slap the -4 to the end. Thus, 15w-4.
nikklg [1K]2 years ago
3 0
6w plus 9w equals 15w 
then -4
so the answer is 15w - 4
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Complete the table by converting each decimal to a fraction. Show your work. Repeating decimals. 0.2, 0.5, 0.7
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<u>Answers </u>

Part 1 = 2/9


Part 2 =5/9


Part 3 =7/9



<u>Explanation</u>

To convert the a repeating decimals this are the steps;

Part 1

Let x = 0.222222... (i)

10x = 2.222222... (ii)


Subtract equation (i) from equation(ii)


10x = 2.222222....

<u> -x = 0.222222....</u>

9x = 2.00000..


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Divide by 9 both sides;


x = 2/9


Part 2

Let x = 0.5555...

10x = 5.5555...

subtract equation (i) from equation (ii).


10x = 5.5555..

<u> - x = 0.5555..</u>

9x = 5.0000..


∴ 9x = 5

x = 5/9


Part 3

Let x = 0.7777....

10x = 7.7777...


Subtracting equation (i) from equation (ii)


10x = 7.7777...

<u> -x = 0.7777...</u>

9x = 7.000..


∴ 9x = 7


x = 7/9


Pattern noted

When converting the repeating decimals to fraction only one number was repeating. This made the three decimals have the same fraction.

5 0
3 years ago
Four circles of unit radius are drawn with centers $(1,0)$, $(-1,0)$, $(0,1)$, and $(0,-1)$. a circle with radius 2 is drawn wit
Reika [66]
Check the picture 1.

The regions contained in an odd number of these 5 circles are

the pink colored region, contained only in the circle with radius 2, 

and the yellow regions, each contained in the intersection of 2 small circles and the third large circle.

So what we need to determine is the "area pink + area yellow".


Consider the second picture.

Let A2 be the area of the right isosceles triangle, and A1 be half of the yellow region.

the region A2 + A1 is called a sector, and it is 1/4 of the area of a unit circle.

A1=A_{sector}-A2= \frac{1}{4} \pi r^2- \frac{1}{2}.1.1= \frac{1}{4} \pi 1^2- \frac{1}{2}=  \frac{1}{4}\pi- \frac{1}{2}


Thus, the overall yellow region is 8A1=8(\frac{1}{4}\pi- \frac{1}{2})=2\pi-4


The purple area is:
 
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(because subtracting all 4 small circles means that each of the 4 separate yellow regions have been subtracted twice)

A_{purple}=\pi.2^2-4(\pi.1^2)+2\pi-4=4\pi-4\pi+2\pi-4=2\pi-4


Finally, the total area is : 2\pi-4+2\pi-4=4\pi-8 (units squared) 



Answer:   6\pi-8    square units

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