Answer:
-71
Step-by-step explanation:
let 'n' = a number
2(143 + 2n) = 0n + 2
2(143 + 2n) = 2
143 + 2n = 1
2n = -142
n = -71
Answer:
a = z/mb
Step-by-step explanation:
Given:
![\displaystyle \large{z=mab}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7Bz%3Dmab%7D)
To solve for a, divide both sides by the variables mb to isolate a-term.
![\displaystyle \large{\dfrac{z}{mb}=\dfrac{mab}{mb}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7Bz%7D%7Bmb%7D%3D%5Cdfrac%7Bmab%7D%7Bmb%7D%7D)
Simplify the expression and we finally have solved for a-term.
![\displaystyle \large{\dfrac{z}{mb}=a}\\\\\displaystyle \large{a=\dfrac{z}{mb}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7B%5Cdfrac%7Bz%7D%7Bmb%7D%3Da%7D%5C%5C%5C%5C%5Cdisplaystyle%20%5Clarge%7Ba%3D%5Cdfrac%7Bz%7D%7Bmb%7D%7D)
Therefore, the answer to this question is a = z/mb.
Please let me know if you have any questions regarding my answer or explanation!
About 204 students would choose summer , I found this because 25% is one quarter of a whole and to get the whole you multiply by four so take 51 and multiply by four to get 204
<em>.... what is this train..... ❓❓</em>
Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have
![2(x+y) =2400 \\ x+y=1200 \\ y = 1200 -x](https://tex.z-dn.net/?f=%202%28x%2By%29%20%3D2400%0A%5C%5C%0Ax%2By%3D1200%0A%5C%5C%0Ay%20%3D%201200%20-x%20)
Let A represents area, and area is the product of length and width .
So we get
![A = x y](https://tex.z-dn.net/?f=%20A%20%3D%20x%20y%20)
Substituting the value of y, we will get
![A = x (1200-x)= 1200x -x^2](https://tex.z-dn.net/?f=%20A%20%3D%20x%20%281200-x%29%3D%201200x%20-x%5E2%20)
Second part
The area is maximum at the vertex, and vertex is
![x = - \frac{1200}{2(-1)} = 600 feet](https://tex.z-dn.net/?f=%20x%20%3D%20-%20%5Cfrac%7B1200%7D%7B2%28-1%29%7D%20%3D%20600%20feet%20)
And
![y=1200-x = 1200-600 = 600 feet](https://tex.z-dn.net/?f=%20y%3D1200-x%20%3D%201200-600%20%3D%20600%20feet%20)
And that's the required dimensions .