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Nuetrik [128]
3 years ago
12

A product code consists of a one-or two-digit number (including 0) followed by 5 not necessarily distinct letters. How many prod

uct codes are possiable?
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer: 1,306,951,360

Step-by-step explanation:

Number of digits in Number system = 10

Number of letters in English Alphabet= 26

Number of ways to product code consists of a one digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10\times26^5   (1)

Number of ways to product code consists of a two-digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10^2\times26^5    (2)

Now, total product codes are possible:         [Adding (1) and (2)] 10\times26^5+10^2\times26^5

=26^5(10+10^2)\\\\=(11881376)(10+100)\\\\=11881376(110)\\\\=1306951360

Hence, the number of product codes are possible = 1,306,951,360

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eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
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3 years ago
Given that P=x+y<br>Find P when:<br>x=11and y=6<br>what is p ?​
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Step-by-step explanation:

<u>Step 1: Define</u>

P = x + y

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y = 6

<u>Step 2: Evaluate</u>

  1. Substitute:                    P = 11 + 6
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