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Nuetrik [128]
3 years ago
12

A product code consists of a one-or two-digit number (including 0) followed by 5 not necessarily distinct letters. How many prod

uct codes are possiable?
Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer: 1,306,951,360

Step-by-step explanation:

Number of digits in Number system = 10

Number of letters in English Alphabet= 26

Number of ways to product code consists of a one digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10\times26^5   (1)

Number of ways to product code consists of a two-digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10^2\times26^5    (2)

Now, total product codes are possible:         [Adding (1) and (2)] 10\times26^5+10^2\times26^5

=26^5(10+10^2)\\\\=(11881376)(10+100)\\\\=11881376(110)\\\\=1306951360

Hence, the number of product codes are possible = 1,306,951,360

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Answer:

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(a)

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3 years ago
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Rudik [331]

Answer:

y=-3x-3

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
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Elanso [62]

Answer:

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Step-by-step explanation:

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The equation of a line is y=mx + b.

x and y are the coordinates of any point on a line.

m is the slope.

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Lines are parallel to each other when they have the same slope. A line parallel to y = 5x + 2 would also have the slope 5.

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y = mx + b

y = 5x + 29

6 0
3 years ago
Can someone help me with the graphing part??
vlabodo [156]

Answer:

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Step-by-step explanation:

Good luck.

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Answer:

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Step-by-step explanation:

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