Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

Answer:
(12/5)m^3
Step-by-step explanation:
It's easier for most of us to write out a fraction / ratio without the " / " symbol:
48m^7
------------
20 m^4
Separate the coefficients from the powers of m:
48 m^7
----- * -------- Now let's reduce each fraction separately:
20 m^4
48/20 = 12/5, and
(m^7) / (m^4) = m^(7-4) = m^3
... so that our final answer is (12/5)m^3.
Answer:
D
Step-by-step explanation:
The sum of two remote interior angles (a remote interior angle is the interior angle that is not supplementary to the exterior angle given -- in this case A and B are remote angles) equals the exterior angle.
In This case A + B = 140
A = x + 2
B = 2x
x +2 + 2x = 140
3x + 2 = 140 Subtract 2 from both sides
3x = 138 Divide by 3
x = 138/3
x = 46
<B = 2x
<B = 2*46
<B = 92
The points (0, 3), (4, 0), (9, 0), (0, 11), and (14, 0) are plotted on the graph. On a coordinate plane, points (0, 3), (4, 0),
Advocard [28]
Answer:
can you take a picture it might make it easier for me
BOTH they both are correct bc they both state the same thing perimeter is both length+ both width's so l+l+w+w=2l+2w