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Nuetrik [128]
4 years ago
12

A product code consists of a one-or two-digit number (including 0) followed by 5 not necessarily distinct letters. How many prod

uct codes are possiable?
Mathematics
1 answer:
Dafna1 [17]4 years ago
5 0

Answer: 1,306,951,360

Step-by-step explanation:

Number of digits in Number system = 10

Number of letters in English Alphabet= 26

Number of ways to product code consists of a one digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10\times26^5   (1)

Number of ways to product code consists of a two-digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-

10^2\times26^5    (2)

Now, total product codes are possible:         [Adding (1) and (2)] 10\times26^5+10^2\times26^5

=26^5(10+10^2)\\\\=(11881376)(10+100)\\\\=11881376(110)\\\\=1306951360

Hence, the number of product codes are possible = 1,306,951,360

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If you start with a number, add 5, then multiply by 7, the result is 133. what was the original number
sergeinik [125]
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____________________________________
 a + 5 = b ;

 b * 7 = 133 .
______________________________________________
What is:  "a" ?
______________________________________________
133 / 7 = 19 = b ;

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Subtract "5" from each side of the equation;
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_______________________________________________
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             a = 14  .
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 Let us check our answer:

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then multiply by "7" :  "19 * 7"
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and the result is: 133 ?
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   19 * 7 = ? 133 ? Yes!
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