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3 years ago

Which point has the coordinate 1.6? Online graphic for number line in online checkpoint A. H B. J C. F D. G

Mathematics

1 answer:

dem82 [27]3 years ago

4 0

The answer is option B i.e., Point F because 0-2 there are 10 divisions and point J is before 2 so it is clear that point J has coordinate 1.6.

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What do scientists usually do if they can't draw clear conclusions?

Dmitry_Shevchenko [17]

Answer:

B. collect more data to support their hypothesis.

D. something the data do not directly show, but that can be found indirectly.

A. agree with the hypothesis.

Step-by-step explanation:

8 0

3 years ago

What is the volume of the square pyramid shown below?

castortr0y [4]

Option A. 150 m 3 is the correct one
$150 \: m {3}$

7 0

3 years ago

in a hotel ,100 bulbs each of 60W are lightened for 6 hours a day and 40 fans each of 50Wvate run for 10 hours a day . calculate

alekssr [168]

Answer:

1680 kwhr

Step-by-step explanation:

See attached for explanation. I converted watt*hr to kW*hr by dividing by 1000.

Fans Bulbs

40 100

50 60 W

10 6 hours/day

20000 36000 W*hr/day

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600 1080 kWhr/month

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5 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

HEYYYY GUYYYSSS HELPP MEEE, ILL MARK YOU BRAINIEST. PLEEEAAASEEEE thankkyouu

VikaD [51]

Answer:

Step-by-step explanation:

A dependent variable in an expression is one whose value can be determined only when the value of other variable (i.e independent) is known.

A. The cost at the fitness center depends on the number of months (x).

The cost is the dependent variable, and number of months (x) is the independent variable.

f(x) = 100 + 40x

Example, the cost paid for 12 months can be determined as;

f(12) = 100 + 40(12)

= 100 + 480

= 580

Thus, $580 would be paid for 12 months at the fitness center.

B. The lettuce is sold at $1.69 per pound. The cost depends on the number of pounds of lettuce bought.

The cost is the dependent variable, while the number of pounds of lettuce (x) bought is the independent variable.

So that;

f(x) = 1.69x

The cost of 10 pounds of lettuce can be determined as;

f(x) = 1.69(10)

= 16.9

Thus, the cost of 10 lb of lettuce is $16.90.

6 0

2 years ago