To be a function every input value can only have one output value
In the given problem the input value 12 has two different output values so this cannot be a function.
Answer: the relation is not a function because an input has two different outputs.
Answer:
5 + 2(3 + 2x) = x + 3(x + 1) (2nd one)
Step-by-step explanation:
The top and bottom question's are all real numbers and the third one is 0
125 . a^3 . b^2
you can also write it as 5^3 .a^3 .b^2
ANSWER:
<u>On solving equation by quadratic formula method, we get</u>
D = b² – 4ac
- (–5)² – 4 × 1 × 3
- 25 – 12
- 13
D > 0, so it has real roots.
Now, x = – b ± √D/2a
So, <u>Correct choice</u> - [A] & [C].
Easy example that shows
:
Let
.
Then
.
So
, or
, and so
.
The basic idea is to find the period of the repeating decimal, move the
digits belonging to one period over to the left of the decimal point by multiplying by
, then subtract the original repeating decimal from this new number, and finally divide by
.
A slightly more complicated example:
Let
.
Then
.
Then
, or