You just have to set the denominator to zero and solve for x
Answer:
see below
Step-by-step explanation:

we need to simplify that

so we can continue

and we can put all together

<h3>
Answer: D) 31</h3>
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Explanation:
The expression g(f(2)) has f(2) as the inner function.
Let's compute f(2)
This means we plug x = 2 into the f(x) function
f(x) = 4x^3 - 10
f(x) = 4(x)^3 - 10
f(2) = 4(2)^3-10
f(2) = 4*8-10
f(2) = 32-10
f(2) = 22
Now we'll plug this into the g(x) function
This is because g(f(2)) = g(22). I've replaced f(2) with 22
So,
g(x) = (3x-4)/2
g(22) = (3*22-4)/2
g(22) = (66-4)/2
g(22) = 62/2
g(22) = 31
Therefore, g(f(2)) = 31
2/3x - 1/2 = 1/3 + 5/6x....multiply the entire equation by the common denominator of 6...this will get rid of the fractions.
6(2/3x - 1/2) = 6(1/3 + 5/6x) =
4x - 3 = 2 + 5x...subtract 5x from both sides
4x - 5x - 3 = 2...add 3 to both sides
4x - 5x = 2 + 3...combine terms
-x = 5...multiply by -1 to make x positive
x = -5