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padilas [110]
3 years ago
13

Patterns and functions​

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0
Anddddddddddddd? what else?
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1,290=h/10+h/5 What is h?​
alekssr [168]

Answer:

4300

h/10 + 2h/10

= 1290

3h/10 = 1290

3h = 12,900

h = 4300

6 0
3 years ago
Read 2 more answers
How do you find vertical asymptotes?
Keith_Richards [23]
You just have to set the denominator to zero and solve for x
7 0
3 years ago
Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

3 0
3 years ago
Consider these functions
Evgen [1.6K]
<h3>Answer:  D) 31</h3>

==========================================================

Explanation:

The expression g(f(2)) has f(2) as the inner function.

Let's compute f(2)

This means we plug x = 2 into the f(x) function

f(x) = 4x^3 - 10

f(x) = 4(x)^3 - 10

f(2) = 4(2)^3-10

f(2) = 4*8-10

f(2) = 32-10

f(2) = 22

Now we'll plug this into the g(x) function

This is because g(f(2)) = g(22). I've replaced f(2) with 22

So,

g(x) = (3x-4)/2

g(22) = (3*22-4)/2

g(22) = (66-4)/2

g(22) = 62/2

g(22) = 31

Therefore, g(f(2)) = 31

7 0
3 years ago
What is the solution to the linear equation? 2/3x-1/2=1/3+5/6x
creativ13 [48]
2/3x - 1/2 = 1/3 + 5/6x....multiply the entire equation by the common denominator of 6...this will get rid of the fractions.

6(2/3x - 1/2) = 6(1/3 + 5/6x) =
4x - 3 = 2 + 5x...subtract 5x from both sides
4x - 5x - 3 = 2...add 3 to both sides
4x - 5x = 2 + 3...combine terms
-x = 5...multiply by -1 to make x positive
x = -5
7 0
4 years ago
Read 2 more answers
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