Answer:
21
Step-by-step explanation:
25*3=75
7*3=21
You will need 3 to 4 yards of concrete for a footer that's 1 foot wide and 12 inches deep.
13x+4y=487------>13x+4y=487----------->13x+4y=487
6x+2y=232-------->-2(6x+2y)=232*-2---->-12x-4y=-464
x=23----> 6(23)+2y=232------->138+2y=232----->2y=94--->y=47
x=ties y=suspenders
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²