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Jet001 [13]
3 years ago
5

Find the area of the triangle to the nearest tenth.

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

42.4

Step-by-step explanation:

1) use this formula of Area of the triangle:

A=\frac{1}{2} a*b*sin(a,b)

2) using the formula described above:

A=0.5*14*11*0.55≈42.4 (mm²)

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The math club made a total of $1155 from selling 210 T-shirts. How much did they sell each T-shirt for?
worty [1.4K]

Answer:

$5.50

Step-by-step explanation:

We need to divide the total amount earned by the number of t-shirts

\frac{1155}{210} = $5.5/shirt

4 0
3 years ago
Solve by factoring 6p^2 =21p-6
uysha [10]

Given,

The expression is:

6p^2=21p-6

By using the middle term splitting method,

\begin{gathered} 6p^2-21p+6=0 \\ 2p^2-7p+2=0 \\ (x-(\frac{7+\sqrt{33}}{4}))(x+\frac{7+33}{4})=0 \end{gathered}

Hence, the factor is (x-(7+sqrt(33)/4)) (x+(7+sqrt(33)/4)).

7 0
1 year ago
What is the circumference of the circle shown below?​
Wittaler [7]
I think the answer is D but in not sure
7 0
3 years ago
Read 2 more answers
Given the preimage and image,find the dilation scale factor.​
Oliga [24]

Answer:

The dilation scale factor is \frac{1}{2}.

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) K' = \alpha_{1} \cdot K

2) T' = \alpha_{2} \cdot T

3) P' = \alpha_{3} \cdot P

4) J' = \alpha_{4} \cdot J

5) \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}

If we know that K = (2, 0), K' = (1, 0), T = (3, 0), T' = (1.5,0), P = (1, 5), P' = (0.5, 2.5), J = (0, 3) and J' = (0, 1.5), then the coefficients are, respectively:

\alpha_{1} = \frac{1}{2}, \alpha_{2} = \frac{1}{2}, \alpha_{3} = \frac{1}{2}, \alpha_{4} = \frac{1}{2}

As \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}, we conclude that the dilation scale factor applied in the preimage is equal to \frac{1}{2}.

7 0
3 years ago
Please van you work out 5/6 of 54
Talja [164]

Answer:

45

Step-by-step explanation:

1/6 of 54= 9

9*5=45

5 0
3 years ago
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