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Rainbow [258]
2 years ago
10

.

Mathematics
1 answer:
Licemer1 [7]2 years ago
3 0

Answer:

At least 4 visits

Step-by-step explanation:

120 - 75 = 45

45/13.5 = 3.33.....

3*13.5 = 40.5

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Answers need to be fractions, if they are not whole numbers. No decimals
klemol [59]

The Slope of lines parallel to line is 1/2 and the Slope of lines perpendicular  to line is -2.

<h3>What is the equation of a straight line ?</h3>

An equation that can be written in the form of y = mx+c

where m is the slope of the line

and c is the intercept on y axis

The equation given in the question is

y=1/2x−7

in this the slope = 1/2

Intercept = -7

For parallel Lines

For a parallel line , the slope of the line is same

and is given by  m = 1/2

For a perpendicular line

Slope will be equal to

-1/m

here -1/m = -2

Therefore the slope for perpendicular line is -2.

To know more about Straight Line equation

brainly.com/question/959487

#SPJ1

7 0
2 years ago
Is this a function? plz help me i need help
LenaWriter [7]

Answer:

yes it is

Step-by-step explanation:

4 0
2 years ago
Tamara's dosage of medication has recently decreased 20 milligrams per day. What is the total decrease in Tamara's medication at
Leviafan [203]
7x20 = 140 making that the total amount of decrease per week. Hope this helps!
6 0
3 years ago
Read 2 more answers
Y=x+3 <br> 2x-y=-1<br> write solution as ordered pair
dsp73

The first equation tells you that y=x+3. If you substitute this expression for y in the second, we have

2x-(x+3)=-1 \iff x-3=-1 \iff x=2

And we can deduce y=x+3=2+3=5

5 0
3 years ago
Triangle EFG has coordinates E (-4,4), F (-4,-2), and G (2,-2). Triangle JKL will be a dilation of triangle EFG with a scale fac
denis-greek [22]

The point L is plotted at A. (1, -1).

Step-by-step explanation:

Step 1:

First, we plot the coordinates of both triangles.

The coordinates of the triangle EFG are as follows;

E = (-4, 4), F = (-4, -2), and G = (2, -2).

The coordinates of triangle JKL are;

J = (-2, 2), K = (-2, -1), and L = (x, y).

Step 2;

Next, we need to find the distances between at least two coordinates for both triangles.

The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

The distance of EF = 4-(-2) =6.

The distance of JK = 2-(-1)= 3.

The distance of FG =2-(-4)= 6.

The distance of KL =  (Scale factor)(the distance of FG),

The distance of KL= (\frac{1}{2} )(6) = 3.

Step 3;

So the point L is 3 points away from point k on the x axis.

(x, y) = (-2+3, 1) = (1, -1).

So point L is plotted at option A. (1, -1).

8 0
3 years ago
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