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sesenic [268]
3 years ago
5

If you could show as much work as possible that would be amazing!!

Mathematics
1 answer:
Nikitich [7]3 years ago
3 0

Answers:

<u>Reduce:</u>

Here we gave to simplify the expressions:

9) x^{2}+7x+\frac{12}{x^{2}}+11x+28

Grouping similar terms:

(x^{2}+\frac{12}{x^{2}})+(18x+28)

Applying common factor x^{2} in the first parenthesis and common factor 2 in the second parenthesis:

x^{2}(1+\frac{12}{x^{4}})+2(9x+14) This is the answer

11) y^{3}+\frac{27}{y^{2}}+2y-3

Rearranging the terms:

(y^{3}+2y)+(\frac{27}{y^{2}}-3)

Applying common factor y in the first parenthesis and common factor 3 in the second parenthesis:

y(y^{2}+2)+3(\frac{9}{y^{2}}-1) This is the answer

<u>Multiply:</u>

19) (\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})

Multiplying both fractions:

\frac{36 a^{9}u^{7}c^{4}}{315 c a^{13}u^{8}}

Dividing numerator and denominator by 3 and simplifying:

\frac{12 c^{3}}{105 c a^{4}u} This is the answer

21) (x-\frac{3}{x}-7)(x^{2}-9x+\frac{35}{x^{2}}-18)

(\frac{x^{2}-3-7x}{x})(\frac{x^{4}-9x^{3}+35-18x^{2}}{x^{2}})

Operating with cross product:

x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})

x^{9} -9x^{8} -18x^{7}+35x^{5}-7x^{8}  +63x^{7}+126x^{6}-245x^{4}-3x^{7}+27x^{6}+54x^{5}-105x^{3}

Grouping similar terms and factoring:

x^{9}-2(8x^{8}+21x^{7} )+153x^{6}+89x^{5}-5(49x^{4}+21x^{3}) This is the answer

<u>Divide:</u>

29) \frac{\frac{k^{6}}{x^{2}}}{\frac{2k^{4}}{3x^{6}}}

\frac{3k^{6}x^{6}}{2x^{2}k^{4}}

Simplifying:

\frac{3}{2} k^{2}x^{4} This is the answer

33) \frac{\frac{x+5}{x+1}}{\frac{x^{2}+11x+30}{x^{2}+3x+2}}

\frac{(x+5)(x^{2}+3x+2)}{(x+1)(x^{2}+11x+30)}

Factoring numerator and denominator:

\frac{(x+5)(x+2)(x+1)}{(x+1)(x+6)(x+5)}

Simplifying:

\frac{x+2}{x+6} This is the answer

37) \frac{\frac{x-10}{x+13}}{\frac{x^{3}-1000}{x^{2}+15x+21}}

\frac{(x-10)(x^{2}+15x+21)}{(x+13)(x^{3}-1000)}

Applying the distributive property in numerator and denominator:

\frac{x^{3}+15x^{2}+21x-10x^{2}-150x-210}{(x+13)(x^{4}-1000x+13x^{3}-13000)}

Grouping similar terms and factoring by common factor:

-\frac{5x(x^{2}-129)(x^{2}-42)}{1000x^{3} (x+13)(x-13)}

Dividing by 5 in numerator and denominator and simplifying:

-\frac{(x^{2}-129)(x^{2}-42)}{200x^{2}(x+13)(x-13)} This is the answer

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Which relation is a function?
yKpoI14uk [10]

Answer:

C

Step-by-step explanation:

if you don't have from same x different outcomes is a function

think that x is a day you count votes, you can not get for the same day different y number of votes ( something is fishy then)

A. not a function because (6, -3) and (6, 3)

B. not  a function because (4,7) and (4,2)

C. is a function

D. not a function because (2, -1) (2,1) (2,3)

4 0
3 years ago
Solve for B -(12 x 2) x (-6) = -12 x (2 x b)<br> A. -6<br> B. 6<br> C. -12<br> D. 12
myrzilka [38]

<u><em>Answer:</em></u>

<u><em>Option A</em></u>

<u><em>Step-by-step explanation:</em></u>

<u><em>-(12 x 2) x (-6) = -12 x (2 x b)</em></u>

<u><em>=> -24 x -6 = -12 x 2b</em></u>

<u><em>=> 144 = -24b</em></u>

<u><em>=> b = -6</em></u>

<u><em>Hoped this helped.</em></u>

5 0
2 years ago
Roundup Racquets restrings tennis racquets for $22. If the store restrings 20 racquets each month, what is the monthly revenue f
ser-zykov [4K]

Answer:

The revenue would be $ 440

Step-by-step explanation:

Consider the correct complete question is,

"Roundup Rackets restrings a tennis racket for $22. If the store restrings 20 rackets each month, what is the monthly revenue from restringing rackets."

Thus,

The price for restrings each tennis racket = $ 22,

Number of rackets re stringed in a month = 20,

Hence, the monthly revenue = price of restrings each tennis racket × number of rackets re stringed

= 22 × 20

= $ 440

7 0
3 years ago
The top of the circular table has a radius of 16 inches.What is the circumfrence of the tabletop? Use 3.14 for pie
puteri [66]

Answer:

100.48

Step-by-step explanation:

Using the formula : 2pi times the radius, I can plug the radius in and find the circumference. 2 times pi is 6.28, and the radius is 16. 6.28 times 16 =  100.48.

8 0
3 years ago
Tia and Ken sold snack bars and magazine subscriptions for the school fundraiser. Tia sold 16 snack bars and 4 magazine subscrip
Aliun [14]

Answer:

The value of the snack bar is $ 2 and that of the magazine subscription is 25 $

Step-by-step explanation:

We have a system of two equations and two unknowns, which would be the following:

let "x" be the cost of the snack bar

Let "y" be the cost of the magazine subscription

16 * x + 4 * y = 132

20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6

replacing:

16 * x + 4 * (190 - 20 * x) / 6 = 132

16 * x + 126.66 - 13.33 * x = 132

2.66 * x = 132 - 126.66

x = 5.34 / 2.66

x = 2

for "y":

y = (190 - 20 * 2) / 6

y = 25

Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $

6 0
3 years ago
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