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2 years ago

4+3(15-2^(3)) Simplify the equation....

Mathematics

2 answers:

miskamm [114]2 years ago

6 0

Answer:

Step-by-step explanation:

$4+3\left(15-2^3\right)\\\\3\left(15-2^3\right)=21\\\\=4+21\\\\=25$

DIA [1.3K]2 years ago

6 0

Answer:

Step-by-step explanation:

4+3(15-2^(3)

4+3(15-(2*2*2)

4+3(15-8)

4+3(7)

4+21=25

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Factor completly x^2 -64

Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

$\left(x+8\right)\left(x-8\right)$

Step-by-step explanation:

⇒ Given info:

Factor completely $x^2 -64$

⇒ Solution:

Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.

$=x^2-8^2$

Applying difference of two squares formula: $x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=x^2-8^2=\left(x+8\right)\left(x-8\right)\\$

$=\left(x+8\right)\left(x-8\right)$

Answer~: $\left(x+8\right)\left(x-8\right)$

xcookiex12

8/19/2022

7 0

2 years ago

Solve these equations. Show solutions on a number line. |x+8|=x+8

statuscvo [17]

Answer:

-8 < x < inf

[-8 , inf )

Step-by-step explanation:

set up a +/- |x + 8| = x + 8

the setup a number line and use test points

3 0

3 years ago

Who is correct jo or alex

REY [17]

Neither Alex nor Jo are correct, because surface area is a 2-dimensional quantity, so it would be given in just square units, not linear nor cubic.

So the answer is D

8 0

2 years ago

Determine the IQR for this set of data. 12, 13, 14, 15, 17, 18, 19, 19, 22, 23 14 17.5

VladimirAG [237]

Answer:5

Step-by-step explanation:

4 0

3 years ago

Consider the following system of equations:

Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

$-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}$

$\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}$

Multiply by 3 both sides

$x^{2}+y^{2}=\frac{5}{2}$ ----> equation A

The equation A is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

and

$5y^{2} =\frac{25}{2}-5x^{2}$

$5x^{2}+5y^{2} =\frac{25}{2}$

Divide by 5 both sides

$x^{2}+y^{2} =\frac{5}{2}$ ----> equation B

The equation B is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0

3 years ago

Read 2 more answers