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3 years ago

If a2=8, what are the first three terms of the sequence defined by the recursive formula below? an=3an-1+2

2 answers:

7 0

The answer is Letter B - 2, 8, 26

Given: an=3an-1+2 ; where a2=8
Required: First three terms of the sequence - a1, a2, a3
Solution:

You need to work back to get a1 since the given is a2.
To work back, minus 2 from 8 first before dividing the number by 3.
a1 = 8 - 2
a1 = 6 / 3
a1 = 2

In getting a3, multiply the given 8 by 3 then add 2. an=3an-1+2 : a3=3(8)+2
a3 = 8 x 3
a3 = 24 + 2
a3 = 26

nordsb [41]3 years ago

4 0

Answer:

The answer is B. I failed this test like five times but I finally figured out its B.

Step-by-step explanation:

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Its #1 and this is for algebra 2

4vir4ik [10]

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3 years ago

Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

AlekseyPX

The answer is
$\frac{-6i-3}{5}$ .

Before we rationalize the denominator, we must simplify the numerator and denominator. We evaluate the square root on the top, and combine like terms on the bottom:
$\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}$

To rationalize the denominator, we multiply by the conjugate. The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign. The conjugate of -2-i is -2+i:

$\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}$

7 0

3 years ago

Need answer for this ratios question

Tom [10]

Answer: 4:1

Step-by-step explanation: I think the answer is 4:1. I think this because 20% of 2500, would be 500. So 2500-500=2000. So the ratio would be 2000:500. Then we simplify 2000:500, by dividing 2000 by 500, and dividing 500 by 500. 500 / 500 = 1. 2000 / 500 = 4, so the answer is 4:1. (I am sorry if I am incorrect)

7 0

3 years ago

Hello how are you today. Question 2(×+-5)+×=×+(-6)

andre [41]

Answer:

x = 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

2(x + -5) + x = x + (-6)

Step 2: Solve for x

[Distributive Property] Distribute 2: 2x - 10 + x = x - 6
[Addition] Combine like terms (x): 3x - 10 = x - 6
[Subtraction Property of Equality] Subtract x on both sides: 2x - 10 = -6
[Addition Property of Equality] Add 10 on both sides: 2x = 4
[Division Property of Equality] Divide 2 on both sides: x = 2

6 0

3 years ago

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57 plus what equals 86

Jet001 [13]

Answer:

Step-by-step explanation:

57+x=86

x=86-57

x=29

3 0

3 years ago

Read 2 more answers