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Leni [432]
3 years ago
15

Please hurry simplify the expression (15^1/5)^5

Mathematics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

15

Step-by-step explanation:

using the rule of exponents

(a^m)^{n} = a^{mn}

(15^{\frac{1}{5)} } ^{5} = 15^{(1/5(5))} = 15^{1} = 15


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F(x) = -x² + 4x - 1 find the value of f(x) if x = 0
ollegr [7]

Answer:

-1

Step-by-step explanation:

Given,

f(x) = -x² + 4x - 1 and x = 0

Putting the value of x we get,

f(0)= -0^{2} + (4 X 0) - 1

    = -0+0-1

    =-1

∴f(x)= -1

So, the required value is -1

8 0
2 years ago
Jason did yard work for 3 hours and earned $18. What are the unit ratios in hours per dollar and dollars per hour?
GalinKa [24]

Answer:

1:6       One hour of work is worth $6

Step-by-step explanation:

$18/3= $6

5 0
4 years ago
Read 2 more answers
a parallelogram has one angle that measures 40. what are the measures of the other three angles in the parallelogram?
KonstantinChe [14]
Since one side is 40°, you subtract that from 180.

180° - 40°= 140°.

So therefore your missing side lengths are 140, 40, and 140.

hopefully this helps





6 0
3 years ago
Read 2 more answers
Offering 40 points and brainliest for answer
Nata [24]
In fact, this problem belongs to the chemistry section.  Recall that many other sciences require mathematical calculations.  The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.

Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute.  Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.

The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g.  Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
8 0
3 years ago
I need help pls help me
lutik1710 [3]

First Method:

Round \frac{3}{5} to the closest integer, which is 1.

Round \frac{3}{4} to the closest integer, which is also 1.

So 1 + 1 = 2.

Answer for method 1: 2

Second Method:

\frac{3}{5} + \frac{3}{4} = \frac{3*4}{5*4} + \frac{3*5}{4*5}  = \frac{12}{20}+\frac{15}{20}=\frac{27}{20}

\frac{27}{20} is around 1

Answer for method 2: 1

The closest answer is 1.

3 0
2 years ago
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