. Find the sum of the first 30 terms of the series:16 + 19 + 22 +......

Mathematics

2 answers:

zepelin [54]3 years ago

5 0

Answer:

1785

Step-by-step explanation:

16+19+22+25+28+31+34+37+40+43+46+49+52+55+58+61+64+67+70+73+76+79+82+85+88+91+94+97+100+103=1785

Bogdan [553]3 years ago

5 0

Answer:

<h3>The answer is 1785</h3>

Step-by-step explanation:

The above sequence is an arithmetic sequence

The sum of an nth term of an arithmetic sequence is written as

$\frac{n}{2} (2a + (n - 1)d)$

Where n is the number of terms

a is the first term

d is the common difference

From the question

n is 30

a is 16

d = 19 - 16 = 3

So the first 30 terms of the series is

$\frac{30}{2} (2(16) + (30 - 1) \times 3) \\ = 15(32 + 29 \times 3) \\ = 15(32 + 87) \\ = 15(119) \\ = 1785$

Hope this helps you.

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