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2 years ago

You have 1000000 small cubes.

Mathematics

1 answer:

Tju [1.3M]2 years ago

8 0

Answer:

1000 in

Step-by-step explanation:

Given

The dimension of the small cube is 1\ in.1 in.

No of the cubes is 10^6106

If the small cubes are arranged on the floor

The area of the cubes is

\Rightarrow 10^6\times 1^2\ in.^2⇒106×12 in.2

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3 years ago

NEED HELP . GIVING BRAINLIEST

andreev551 [17]

Answer:

There are 108 inches in 9 feet

Step-by-step explanation:

Well, two unit multipliers mean we have to convert through two units before we arrive at our final answer so we can convert from feet to yards to inches!

We know that 3 feet equal a yard, right?

So we can divide 9 by 3 to get the amount that 9 feet translates to in yards.

$9/3 = 3!$

So we are now done with our first conversion! Our second is going to be from yards to inches!

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2 years ago

The ratio of the measures of the sides of a triangle is 9:12:5. If the perimeter of the triangle is 130 feet find the measures o

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2 years ago

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In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen

Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type ni xi si

Graded 42 0.486 0.187

No-fines 42 0.359 0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

Test statistic :

$Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}} + \frac{s_{2}^{2} }{n_{2}} } }$

$Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42} + \frac{0.02496 }{42} } }$

$Z = \frac{0.127 }{\sqrt{0.001468}}$

$Z = \frac{0.127 }{0.0377}$

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

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2 years ago