Answer:
a = 3.21 10⁻⁸ m / s²
, The correct answer is E
Explanation:
For this exercise we will use Newton's second law, where the force is the gravitational attraction force, the attached diagram shows the forces and their components in a horizontal and vertical coordinate system, due to the symmetry of the equilateral triangle the horizontal components be annulled and the two vertical components add up; let's write Newton's education for the vertical axis (Y)
2 = m a
Let's use trigonometry to find the components
sin 60 = / F
= F sin60
2 F sin60 = m a
The gravitational force equation is
F = G m M / r
The mass of the entire sphere is equal to m = M and the distance between the spheres is the side of the equilateral triangle
F = G m² / L²
We replace
2 (G m² / L²) sin60 = m a
a = 2 G m / L² sin 60
Let's calculate
a = 6.67 10⁻¹¹ 50 / 0.30² sin 60
a = 3.21 10⁻⁸ m / s²
The correct answer is E
Answer: 72200
Explanation:
First you must find the height for this is on an inclined hill using:
h=Lsin(angle) —> 28.0sin(11.0) = 5.34
Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.
Using mgh:
m=1380
g=9.80
h=5.34
(1380)(9.8)(5.34)
=72218.16
*Rounding to the 3rd=72200
Hope this helps :)
Longitudinal wave hope this is right :))))))))))
Answer : The best pressure is 110 GPa of the lower mantle.
Explanation : We know that the pressure in the lower mantle starts at 24 GPa and reach a 136 GPa at the boundary.
So, the best pressure is 110 GPa because 220 GPa, a 305 GPa and 360 GPa are the higher value of the maximum value 136 GPa of the lower mantle.
Answer:
Explanation:
The centripetal force experienced by the steel toolbox is provided by the friction between the toolbox and the bed of the truck.
Therefore,
--------------------------------(1)
Here,
v - speed of truck
m - mass of toolbox
r - radius of curve around which the truck is turning
f - frictional force
μmg
In order to obtain Vmax, frictional force must also be max
Thus,
f = μmg--------------------------------------------------(2)
Substitute (2) in (1)
μmg
μgr
g - 9.8 m/
The standard value of coefficient of static friction between steel and steel is
μ ≈ 0.7
Therefore,