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IgorLugansk [536]
3 years ago
15

How many parallel and perpendicular lines, are there in a trapezium?

Mathematics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

<u>US</u>

  • 0 parallel lines
  • optionally, one or two (opposite) angles may be 90°

<u>World</u>

  • 2 parallel lines
  • optionally, one line perpendicular to the two parallel lines

Step-by-step explanation:

It depends on where you are. A "trapezium" outside the US is the same as a "trapezoid" in the US, and vice versa.

A trapezium (World; trapezoid in the US) is characterized by exactly one pair of parallel lines. One of the lines that are not parallel may be perpendicular to the parallel lines, but that will only be true for the specific case of a "right" trapezium.

__

A trapezium (US; trapezoid in the World) is characterized by no parallel lines. It <em>may</em> have one angle or opposite angles that are right angles (<em>one or two sets of perpendicular lines</em>), but neither diagonal may bisect the other.

In the US, "trapezium" is rarely used. The term "quadrilateral" is generally applied to a 4-sided figure with no sides parallel.

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Answer: Time taken by him in going = 8 hours

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Step-by-step explanation:

Let the total distance from home to New York is x miles,

\text{ Since, Time} = \frac{\text{Distance}}{\text{Speed}}

Also, he drove his car from his home to New York at the rate of 45 mph,

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And, returned over the same road at the rate of 40 mph.

⇒  \text{ Time taken by him in returning } = \frac{x}{40}\text{ hours}

According to the question,

Time taken by him in returning - Time taken by him in going = 30 minutes = 1/2 hours,    ( 1 hours = 60 minutes )

⇒ \frac{x}{40}-\frac{x}{45}=\frac{1}{2}

⇒ \frac{9x}{360}-\frac{8x}{360}=\frac{1}{2}

⇒ \frac{x}{360} = \farc{1}{2}

⇒ 2x=720

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Hence, the total distance from home to New York = x miles = 360 miles

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⇒  \text{ Time taken by him in returning } = \frac{x}{40}\text{ hours}

=\frac{360}{40}=9\text{ hours}

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。☆✼★ ━━━━━━━━━━━━━━  ☾  

It makes more sense if you think about it in numerical terms.

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