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adell [148]
3 years ago
14

36(1/3)^n-1 first five term of the sequence

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Answer:

Step-by-step explanation:

first term:  put n = 1

36(1/3)^n-1 = 36(1/3)^1-1 =12 - 1 = 11

2nd term:  put n = 2

36(1/3)^n-1 = 36(1/3)^2-1 = 19.784

3rd term:  put n = 3

36(1/3)^n-1 = 36(1/3)^3-1 = 0.3333

4th term:  put n = 4

36(1/3)^n-1 = 36(1/3)^4-1 = -0.5555

5th term:  put n = 5

36(1/3)^n-1 = 36(1/3)^5-1 =-0.85185

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