Question

Evaluate x(y-z)2 for =-1,y=5,and z=

Answer 1

Answer:

The value of $x(y-z)^2$ is -16.

Step-by-step explanation:

We need to evaluate $x(y-z)^2$ for x = -1, y = 5 and let us assume that z = 1

It can be simply done by putting the values of x,y and z in the given expression.

$x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2$

We know that the value of 4² = 16

So,

$x(y-z)^2=16\times -1\\\\=-16$

So, the value of $x(y-z)^2$ is -16.