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3 years ago

6

Some engines require oil to be mixed with gasoline. For every gallon of gas used, 4 ounces of oil should be added. How much gas

is needed if 12 ounces of oil are used?

1 answer:

kherson [118]3 years ago

3 0

3 gallons of gas are needed

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Nathan wants to buy a car that costs $25,920 he has $3,000 as a down payment and his payments will be $450 for 6 years through r

sesenic [268]

he payed 3,000 in hand payment then gave checks per...mnth for 6 years to equal the needed amount

3 0

3 years ago

Teresa drove on monday tuesday and Wednesday. On monday her driving distance was 120 miles. The ratio of Wednesdays distance is

SSSSS [86.1K]

Answer:

Teresa drive <u>90 miles</u> on Tuesday.

Step-by-step explanation:

Given:

Teresa drove on Monday, Tuesday and Wednesday.

On monday her driving distance was 120 miles.

The ratio of Wednesdays distance is 3/5.

The ratio of Wednesdays distance to Tuesday's distance is 5/4.

Now, to find the miles Teresa drive on Tuesday:

Teresa driving distance on Monday was = 120 miles.

Her driving distance on Wednesday is = $\frac{3}{5}\ of\ 120.$

$=\frac{3}{5} \times 120\\\\=0.6\times 120\\\\=72\ miles.$

Now, her driving distance on Tuesday is:

$\frac{5}{4} \ of\ 72\\\\=\frac{5}{4} \times 72\\\\=1.25\times 72\\\\=90\ miles.$

Therefore, Teresa drive 90 miles on Tuesday.

7 0

3 years ago

Do the following lengths form a right triangle?

Dmitry_Shevchenko [17]

Answer:

yes, this forms a right angle

5 0

2 years ago

What is the answer??????

dexar [7]

Answer:

38 5/28

Step-by-step explanation:

Well start with the whole numbers 24 and 13 This is adding so that means everything has to be added together. 13+24=37 Now, lets go the fractions.

Find the LCD (Least Common Denominator) of 3/4 and 3/7 and rewrite to solve with the equivalent fractions. (remember the Denominator is the BOTTOM PART of the Fraction. Such as the 4 in 3/4.)

LCD = 28

21/28 + 12/28 = 33/28 which can be simplified to 1 5/28. Combining the whole and fraction parts 37 + 1 + 5/28 = 38 5/28 And that will be your answer. Another way you can do this is

converting mixed numbers to fractions Meaning put them in improper form where the numerator (the top number of a fraction is bigger than the denominator such as 4/3) , our initial equation becomes, 99/4 + 94/7

Applying the fractions formula for addition,

(99×7) + (94×4) / 4×7

= 693+376 / 28 =

= 1069/ 28

Simplifying 1069/28, the answer is

= 38 5/28

And one more thing. An easier way to make a mixed number a improper fraction is the multiply the denominator by the whole number then add the numerator and whatever the denominator is it stays for example

38 5/28.

28 times 38 = 1064 then add the 5 and you get 1069! But we aren't done yet, the denominator was 28 so that means the full answer is 1069/28 and that is the Improper fraction form!

Hope this helps! (sorry I took so long)

~R.C aka dj

6 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

3 years ago